Every man dances with 3 women and every woman dances with 3 men.And also 2 men have 2 women in common in the party. How many people attended the party?

• Men -- M1, M2... etc
  Women -- W1, W2.. etc
  
  the pair can we arranged this way --
  
  M1-W1; M1-W2; M1W3 -- FIRST PAIR
  
  Now, we have a condition -- each men has exactly 2 women in common.
  so, we need 1 extra woman for next pair
  
  M2-W1; M2-W2; M2W4
  LIKEWISE, WE CAN ARRANGE MEN FOR W4 AS WELL.
  
  M3-W1; M3-W3; M3W4
  Last Pair; -- M4-W2; M4-W3; M4-W4
  TOTAL --
  
  4 Men -- M1 M2 M3 M4
  4 Women -- W1 W2 W3 W4 = 8
• 12 years agoHelpfull: Yes(11) No(5)
• ans 4men & 4 women
  
  m1-w1 w2 w3
  
  m2-w1 w2 w4
  
  m3-w3 w4 w1
  
  m4-w2 w4 w3
• 10 years agoHelpfull: Yes(3) No(2)
• ans. 8....
• 12 years agoHelpfull: Yes(0) No(3)
• 4men & 4 women
  m1-w1 w2 w3
  m2-w1 w2 w4
  m3-w3 w4 w1
  m4-w2 w4 w3
• 6 years agoHelpfull: Yes(0) No(0)
• if 1M dance with 3 Womens and
  1W dance with 3 mens then
  this means that 3 mens are dance with 3 womens = 6 peoples ,
  but now in the party 2 mens and 2 womens are present = 4 peoples are now present
  then 6-4 = 2
  add that 2 in the 6members then w will get the total number of people in the party they are = "8"
• 1 year agoHelpfull: Yes(0) No(0)