A person have 2 types of pair of socks. Total 10 pairs exists in a bag. If he selected 3 socks from bag at random, find the probability of selecting atleast one pair of socks.

• probability=1 because in 3 selection always one pair exist
• 10 years agoHelpfull: Yes(44) No(35)
• 10 pairs (i.e, 10L & 10R)
  n(s)= 20C3
  selecting 3 socks, atleast one pair of socks is 2*10C2*10C1
  probability = 2*10C2*10C1/20C3 = 15/19
• 10 years agoHelpfull: Yes(26) No(8)
• 10 pairs means 10 L and 10 R
  SO, ((10C1*10C2)+(10C2*10C1))/20C3
• 10 years agoHelpfull: Yes(17) No(2)
• plz declare which is crt answr at last
• 10 years agoHelpfull: Yes(5) No(0)
• probability 1
  
• 10 years agoHelpfull: Yes(4) No(4)
• there are 5 pairs each of two different types of socks.
  let we have type a and type b socks
  all of the three sock from type a or type b
  1 sock from type a and 2 sock from type b
  2 sock from type a and 1 sock from type b
  in all of these three case there is one pair of sock
  hence,probability=1
  
  
• 10 years agoHelpfull: Yes(3) No(7)
• Given that there are only 2 types of socks. So while selecting 3 socks we can have (2 same and 1 different)
  Therefore we get 100% i. e. probability 1
• 10 years agoHelpfull: Yes(3) No(3)
• probability is 1,
  because it is given that two types of pair exists that means if 5 pair is of one colour than another 5 will be of different colour . therefore by selecting 3 socks it is confined that one pair always exists . may be it is of ano coclour or of other.
• 10 years agoHelpfull: Yes(3) No(1)
• 20c1*1c1*18c1/20c3=3/19
• 10 years agoHelpfull: Yes(2) No(9)
• 15/19 is correct answer...
• 10 years agoHelpfull: Yes(2) No(2)
• if a person has 2 pairs of socks. then after he selected randomly 3 socks there should be one pairs of socks this is certain event so probability=1 to find atleast one pair of socks
• 10 years agoHelpfull: Yes(2) No(0)
• 1
  AS ALL SHOCKS ARE SAME PROBSBILITIY IS 1
  
• 10 years agoHelpfull: Yes(1) No(6)
• ans. should be 3/19
  
  since 3 socks are chosen therefore 1 pair is for sure chosen among them..
  to choose that one pair we have: 10C1.
  from the left 18 socks we have to now choose 1 more sock therefore: 18C1.
  this selection of 3 socks is done from a total of 20 socks therefore: 20C3.
  
  hence the expression becomes:
  
  (10C1*18C1)/(20C3)= 3/19
• 10 years agoHelpfull: Yes(1) No(5)
• 2*10c2*10c1/20c3=15/19
• 10 years agoHelpfull: Yes(1) No(1)
• answer is :1
• 10 years agoHelpfull: Yes(1) No(2)
• [10c1 * 18c1]/20c3
• 10 years agoHelpfull: Yes(0) No(3)
• (10c1/20c1)*(10c1/19c1)*(9c1/18c1)==5/38
• 10 years agoHelpfull: Yes(0) No(1)
• 7/24
  if he takes out 7 shocks out of 10 then he had definitely 1 pair of shocks so,
  7c3/10c3
• 9 years agoHelpfull: Yes(0) No(0)
• Since there are 10 pair means 20 socks nd he choose 3.. For atleast 1 we have 1-(20*18*16/20 p 3)
• 9 years agoHelpfull: Yes(0) No(0)