If all the factors of 5040 are written in ascending order then which will be 55th factor from beginning?

• the total factors are 5040=2^4*3^2*5*7=(4+1)(2+1)(1+1)(1+1)=60
  
  so
  1*5040
  2*2520
  3*1680
  4*1260
  5*1008
  6*840
  .....
  
  55th factor is 840
• 10 years agoHelpfull: Yes(43) No(3)
• 840???
  5040 has got 60 factors...
  6*840=5040
• 10 years agoHelpfull: Yes(5) No(1)
• 5040 = 2^4 × 3^2 × 5^1 x 7^1
  
  Number of divisors = (4+1)(2+1)(1+1)(1+1) = 60
  
  So 55th factor from beginning is also the 6th factor from the end
  
  60th = 5040
  59th = 5040/2 = 2520
  58th = 5040/3 = 1680
  57th = 5040/4 = 1260
  56th = 5040/5 = 1008
  55th = 5040/6 = 840
• 8 years agoHelpfull: Yes(2) No(0)
• 5040 factors are ascending order 2,4,6,8,10........
  these are in a.p
  in a.p nth term is a+(n-1)d
  so 55th term is 2+54(2)=110
  
• 10 years agoHelpfull: Yes(1) No(16)
• Which is the right ans?
• 10 years agoHelpfull: Yes(1) No(0)
• the factor will be 2,4,6,8,10,12,14,16,18,20.......... here this series in a.p with first term 2 and cd=2
  so 55Tth term will be =2+(55-1)*2=110. i think this is the correct answer.
  
• 8 years agoHelpfull: Yes(0) No(1)