How many numbers are there that appear in both of arithmetic progression 4,11,18,25,...2020 and 4,13,22,31,40.....2020?

• Is it 33???
  4 is common to both
  Next no that will be common is 67(LCM of 9,7) +4)
  N last term is 2020
  4+(n-1)63=2020
  N=33
• 10 years agoHelpfull: Yes(23) No(2)
• 4,11,18,25,...2020 and 4,13,22,31,40,...2020
  d=7 and 9
  d=63,a=4
  a+(n-1)d=2020
  4+(n-1)63=2020
  4+(63n-63)=2020
  63n=2099
  n=33
• 10 years agoHelpfull: Yes(11) No(0)
• total terms in 4,11,18,25,....,2020 are 289
  total terms in 4,13,22,31,40...,2020 are 225
  every comman number in first sequence is at 9th number
  every comman number in second sequence is at 7th number
  so 225/7=32+1 (4 is first number)
  so ans is 33
• 10 years agoHelpfull: Yes(9) No(2)
• answer 35
  4,76, TILL 2020 TOTAL=35
  
• 10 years agoHelpfull: Yes(4) No(2)
• a=4
  d=7
  l=2020
  l=a+(n-1)d
  2020=4+(n-1)7
  n=289
• 10 years agoHelpfull: Yes(0) No(6)
• total terms in 4,11,18,25,....,2020 are 289
  total terms in 4,13,22,31,40...,2020 are 225
  every comman number in first sequence is at 9th number
  every comman number in second sequence is at 7th number
  so 225/7=32+1 (4 is first number)
  so ans is 33
• 10 years agoHelpfull: Yes(0) No(1)