Consider the sequence of numbers 0 2 2 4 Where for n 2 the nth term of the sequence is

easy problem

let the x is the number of terms that gives the sum of the terms is 2771

20 terms gives sum is 80
x terms gives sum is 2771
cross product
20*2771=80*x
x=692.5
it is nearly 693 so this is the answer
6 years agoHelpfull: Yes(8) No(0)
here the answer is n=35.
Because the given sequence repeats itself after 20 terms(u can count).
Also the sum of these 20 terms is 80.
so 80 should be added 35 times for which sn>2771.
Hence the answer is n=35.
9 years agoHelpfull: Yes(6) No(30)
0 2 2 4 6 0 6 6 2 8 0 8 8 6 4 0 4 4 8 2 0 2 2...this series will be repeated after every 20 terms
sum of 20 terms of series=80
2771/80 =34 (quotient) and =51 (remainder)
sum of 13 terms =52
34*20=680
So, number of terms is 680+13 =693.
8 years agoHelpfull: Yes(5) No(2)
how this series come?
8 years agoHelpfull: Yes(2) No(3)
0,2,2,4,6,10,16,25,42,58,110,178,288,466,754,1220,1974,3194........

for n=16 sum of series will be 3182
9 years agoHelpfull: Yes(0) No(7)
700
i dont know please tell me
8 years agoHelpfull: Yes(0) No(4)
pls tell me why in ths solution sum of 13 terms taken?

please tell me asap?
8 years agoHelpfull: Yes(0) No(2)
how sum of 20 term become 80
7 years agoHelpfull: Yes(0) No(0)
how this series will come??
7 years agoHelpfull: Yes(0) No(0)
How the series comes
6 years agoHelpfull: Yes(0) No(0)
series is come after adding last no with present one and writing its unit digit
e.g: 0+2=2, 2+2=4, 4+2=6, 4+6=10 so 0 only and so on
6 years agoHelpfull: Yes(0) No(0)

Consider the sequence of numbers 0, 2, 2, 4,... Where for n > 2 the nth term of the sequence is the unit digit of the sum of the previous two terms.
Let sn denote the sum of the first n terms of this sequence. what is the smallest value of n for which sn>2771?