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Numerical Ability
Permutation and Combination
7 different objects are divided among 3 different person,so that either one or two of them do not get any object.how many such combinations are possible?
Read Solution (Total 10)
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- Case 1 :
Two of them do not get any object,
this means all 7 Different objects is given to only one person.
But there are 3 different person hence
No. of ways (N1)= 3 Ways (007,070,700)
Case 2:
One of them do not get any object.
Hence the other 2 will get the 7 different objects.
This is done in 6 ways i.e (160,250,340,430,520,610)
again there are 3 different persons
hence
No. of ways (N2) = 3*6 = 18
Total no. of ways = N1+N2= 3+18 = 21 - 10 years agoHelpfull: Yes(12) No(4)
- here by prob we can say that if any 2 dont get any obj.total obj goes to 3rd person in 3 way.
if 1 of them dont get object then 7 object goes to 2 person
(1,6)=7c1
(2,5)=7c2
(3,4)=7c3
(4,3)=7c4
(5,2)=7c5
(6,1)=7c6
total 7c1+7c2+7c3+7c4+7c5+7c6=126
for 2 person two way=2*126=378
3rd person get the object in 3 way
so tatal =3+378=381 way Ans - 10 years agoHelpfull: Yes(9) No(10)
- if 2 dont get object then 7 objects will go to one person in 3ways...3c1
if 1 dont get obect then 7 objects go to 2 persons
(1,6)=7c1
(2,5)=7c2
(3,4)=7c3
(4,3)=7c4
(5,2)=7c5
(6,1)=7c6
total=126
2 persons is selected among 3 persons in 3c2 ways
hence 3*126+3=381 - 10 years agoHelpfull: Yes(6) No(0)
- case 1: two of them do not get any object:
7C1=7 ways=7
case 2: one of them do not get any object:
7C2 * 3C2= 21*3=63
total combinations= 63+7=70 - 10 years agoHelpfull: Yes(1) No(1)
- ans is 3^7
r^n here r is persons and n is different things - 10 years agoHelpfull: Yes(0) No(3)
- ans is 84 as there will be two case case 1 if 1 person doesnot get anything in case no of combinations will be 3c1*7C2 and case 2 when 2 person will get nothing then no of combinations will be 3C2*7C1
so ans = 3C1*7C2+3C2*7C1 = 84 - 10 years agoHelpfull: Yes(0) No(2)
- can any one tell me the correct answer plz!
- 10 years agoHelpfull: Yes(0) No(1)
- since it is possible to give no objects to one of two person,then we would hv 3choices..for giving each item..3*3*3*3*3*3*3
2187 - 10 years agoHelpfull: Yes(0) No(1)
- I guess, here we can select either of 1 and 2 in two ways,,
so we should use 2*7c2 == 42 is answer i guess.. - 10 years agoHelpfull: Yes(0) No(0)
- for 2 person two way=2*126=378
3rd person get the object in 3 way
so tatal =3+378=381 way - 10 years agoHelpfull: Yes(0) No(0)
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