How many integers lie between 300 and 1000 ,
which are exactly divisible by 13.
a. 53
b. 50
c. 48
d. 45

• a)53
  312...........988
  tn= a+(n-1)d
  988= 312+(n-1)13
  solving n=53
• 10 years agoHelpfull: Yes(23) No(0)
• 312,325,.........988
  a=312,d=13,tn=988
  tn=a+d(n-1)
  988=312+(n-1)13
  52=n-1
  n=53
  
• 10 years agoHelpfull: Yes(2) No(0)
• first number divisible by 13 after 300 is 312 and last number less than 1000 div by 13 is 988.
  so formula
  [(988-312)13]+1
  ans is 53
• 10 years agoHelpfull: Yes(1) No(0)
• 1000/13= 76 +remainder
  300/13=23 +remainder
  76-23=53
• 10 years agoHelpfull: Yes(1) No(0)
• answer is 53. first integer is 312 and last is 988 so using ap we can find out. 988= 312 + (n-1)13
• 10 years agoHelpfull: Yes(0) No(0)
• 53 is the ans
  
• 10 years agoHelpfull: Yes(0) No(0)
• 53.. 13*24=312 .. 13*76=988
  76-24=54
• 10 years agoHelpfull: Yes(0) No(0)
• 53 is the correct answer, because the simplest ever Explaination is here.
  988 - 312= 676 (Subtract the No. greater than 300 which is divisible by 13 from the No. below 1000 which is divisible by 13)
  Now,
  676/13 =52 (Divide the previous Answer by 13)
  52 + 1 = 53 (Add 1 to previous Answer)
  
  Summary:
  --------------
  The word Between means 300 and 1000 will not be considered, If it is divisble or not.
  So the No. next to 300 that is divisible by 13 is 312 (13x24=312) &
  the the No. next before 1000 that is divisible by 13 is 988 (13x76=988)
  Subtract the value before 1000 which is divisible by 13 from the value next to 300 which is divisible by 13.
  After that Divide the answer by 13 and then Add 1 to it.
  
  Done
  --------
  Regards
  NAVEED AKHTAR
• 5 years agoHelpfull: Yes(0) No(0)
• 312,325,338.................988
  a=312 d=13 an=988
  an=a+(n-1)d
  988=312+(n-1)13
  988=312+13n-13
  988=299+13n
  13n=689
  n=53 Answer
• 5 years agoHelpfull: Yes(0) No(0)