The milk and water in two vessels A and B are
in the ratio 4 : 3 and 2: 3 respectively. In what
ratio, the liquids in both the vessels are mixed to
obtain a new mixture in vessel C containing half
milk and half water?
a) 8 : 5 b) 9 :4 c) 5: 7 d) 7 : 5

• Milk in 1 litre mixture of A = 4/7 litre.
  Milk in 1 litre mixture of B = 2/5 litre.
  Milk in 1 litre mixture of C = 1/2 litre.
  By rule of alligation we have required ratio X:Y
  
  X : Y
  4/7 2/5
  
  /
  (Mean ratio)
  (1/2)
  /
  (1/2 – 2/5) : (4/7 – 1/2)
  1/10 1/1 4
  
  So Required ratio = X : Y = 1/10 : 1/14 = 7:5
• 10 years agoHelpfull: Yes(17) No(0)
• take 1 quantity
  milk in 1st vessel 4/7
  milk in 2nd vessel 2/5
  mixture 1/2
  apply mixture alligation method
  u will get 1/10 : 1/14
  = 7:5
• 10 years agoHelpfull: Yes(1) No(0)
• consider either milk or water ...
  If u consider milk :
  milk be re.1 per litre.
  1 lit milk mixture of A=4/7 lit; milk in 1 lit mixture of b=2/5
  For c=1/2 lit.
  C.p of 1 liter in A= Rs.4/7
  C.p of 1 liter in B=Rs.2/5
  mean price=Rs.1/2,
  By the using alligation
  4/7( mix.in A) 2/5( mix.in B)
  /
  1/2
  /
  1/10 1/14
  [mean price- mix.B] [mix.A-mean price]
  req ratio=1/10:1/4
  =7:5
  
• 10 years agoHelpfull: Yes(0) No(0)
• ratio of milk in A = 4/7
  ratio of milk in B = 2/5
  ratio of milk in C = 1/2 ,
  subtract the mean value 1/2 with the ratio's 2/5,4/7
  required ratio is 7:5
• 10 years agoHelpfull: Yes(0) No(0)
• ANS IS D 14/10
• 10 years agoHelpfull: Yes(0) No(0)