Two letters are selected at random from the set of English alphabets
what's the probability that
1)both are vowels?
2)both are consonants?
3)one is vowel and the other is consonant?

• 1) 5C2/26C2=2/65
  2) 21C2/26C2= 42/65
  3) (5C1*21C1)/26C2=21/130
• 9 years agoHelpfull: Yes(61) No(4)
• I Love You Anjana Kumari.
• 9 years agoHelpfull: Yes(16) No(14)
• @gaurav kumar
  1 and 2 are correct
  but i think 3rd is wrong bcoz
  event is "1 vowel and 1 consonants"
  but according to ur solution it is "1 vowel or 1 consonant"
  so the correct solution would be
  1 vowel=(5c1)/(26c1)=5/26 and 1 consonant=(21c1)/(26c1)=21/26
  and since both are inclusive
  so answer will be (5/26)*(21/26)
• 9 years agoHelpfull: Yes(8) No(6)
• 1) 2/65
  2) 42/65
  3) 21/65
• 9 years agoHelpfull: Yes(5) No(2)
• 1. (5c2)/(26c2)=2/65
  2. (21c2)/(26c2)=42/65
  3. (5+21)/(26c2)=2/25
• 9 years agoHelpfull: Yes(4) No(6)
• 1)5C2/26C2
  2)21C2/26C2
  3)5C1*21C1/26C2
• 9 years agoHelpfull: Yes(3) No(0)
• 5c2/26c2=2/65
  21c2/26c2
  5c1.21c1/26c2
• 9 years agoHelpfull: Yes(2) No(0)
• 1) 2/65
  2) 42/65
  3) 21/130
• 9 years agoHelpfull: Yes(2) No(0)
• ANSWER==>
  1. 5C2/26C2 = 10/325= 2/65
  2. 21C2/26C2 = 210/325 = 42/65
  3. (5C2+21C2)/26C2 = 220/325 = 44/65
• 9 years agoHelpfull: Yes(1) No(11)
• 1. (5c2)/(26c2)
  2. (21c2)/(26c2)
  3. (5*21)/(25*26)
  this is correct
• 9 years agoHelpfull: Yes(1) No(0)
• 1) 5C2/26C2=2/65
  2) 21C2/26C2= 42/65
  3) (5C1*21C1)/26C2=21/130
• 9 years agoHelpfull: Yes(1) No(0)
• 1)Here we have to pick both vowels so,
  5c2/26c2=2/65
  2)Here we have to pick both consonants so,
  21c2/26c2=42/65
  3)Here we have to pick one is vowel and the other is consonant so,
  according to question we have to perform and operation
  (5C1*21C1)/26C2=21/130
  
• 9 years agoHelpfull: Yes(1) No(0)
• Answer to third will be :
  (5/26*21/25)+(21/26*5/25) or 2*21/26*5/25 as either of vowel or consonant can occur in the first and second selection.
• 9 years agoHelpfull: Yes(1) No(0)
• 1) (5/26)*(4/25)= 2/65
  
  2) (21/26)*(20/25)= 42/65
  
  3) for vowel (5/26)* for consonant (21/25)= 21/130
• 9 years agoHelpfull: Yes(1) No(0)
• 1) 5C2/26C2=2/65
  2) 21C2/26C2= 42/65
  3) (5C1*21C1)/26C2=21/65
• 7 years agoHelpfull: Yes(1) No(0)
• you r correct @pandey
• 9 years agoHelpfull: Yes(0) No(0)
• 1. 5c2/26c2
  2. 21c2/26c2
  3.5c1*21c1/26c2
• 9 years agoHelpfull: Yes(0) No(0)