there are two candidates p and q in an election.During the
campaign,40% of the voters promised to vote for P ,and rest
for Q.however, on the day of election 15% of the voter went
back on their promise to vote for P and instead voted for Q.
25% of the voters went back on their promise to vote for Q
and instead voted for P.suppose,P lost by two votes,then
what was the total no. of voters.

• let X is total voters
  P Get votes=.4X-(.15*.4x)+(.25*.6X)=.49X
  Q Get votes=.6X-(.25*.6X)+(.15*.4X)=.51X
  According to condistion
  Q-P=2
  .51X-.49X=2
  X=100
• 10 years agoHelpfull: Yes(3) No(0)
• let total voters=x
  promised voter for P & Q are 0.4x and 0.6x respectively.
  15% of P back on their promise and voted Q i.e 0.06x less in P but that no. of voters will increase in Q.25% of Q back on promise and voted P i.e 0.15x less in Q but increase in P.
  i.e votes of P=0.4x-0.06x+0.15x=0.49x
  votes of Q=0.6x+0.06x-0.15x=0.51x
  0.49x+2=0.51x
  so x=100.
• 10 years agoHelpfull: Yes(2) No(0)
• 40% promised to vote for P i.e 4 votes goes to P out of 10 and thus 6 votes to Q
  i.e P =4 votes as promised but 15% went back So ,
  p = 4 * 85%=3.4 votes
  
  and 4-3.4= 0.6 votes goes to Q.
  
  now Q has 6 votes out of 10 but 25% went back
  so Q= 6*75%=4.5 votes
  actual Q votes =4.5+0.6=5.1 votes
  actual P votes= 3.4+1.5=4.9 votes
  given P -Q=2
  .2=2
  therefor, 1=10
  therfore ,10 (initially taken as total votes) = 100 ans
  
  
  Now
• 6 years agoHelpfull: Yes(1) No(0)