ax^4-bx^2+x+5 and f(-3)=2 then f(3)=?

• f(-3)=a(-3)^4-b(-3)^2-3+5
  2=81a-9b+2
  81a-9b=0
  now,
  f(3)=81a-9b+3+5
  f(3)=8[since 81a-9b=0]
• 10 years agoHelpfull: Yes(15) No(0)
• F (-3)=81a-9b+2
  2=81a-9b+2
  0=81a-9b
  F (3)=81a-9b+8
  =0+8:8
• 10 years agoHelpfull: Yes(2) No(0)
• ax^4 + bx^2 + x +5
  here the power 4 and 2 has no effect of + or - in 3
  but value of x will change
  in f(-3) = a(-3)^2 + b(-3)^2 + (-3) + 5 = 2;
  except the (-3) all will be unchanged when x will be x = 3
  so at the place of -3+5=2
  there will be 3+5 = 8
• 10 years agoHelpfull: Yes(1) No(1)
• 8;
  ax^4-bx^2=0 for x=-3,+3
  then f(3)=3+5=8
• 10 years agoHelpfull: Yes(1) No(1)
• f(-3)=2 given
  a(-3)^4-b(-3)^2-3+5
  f(-3)=81a+9b+2
  2 = 81a+9b+2
  cancel 2 on both sides
  81a+9b=0
  f(3)=a(3)^4-b(3)^2+3+5
  = 81a+9b+8
  =0+8
  =8
  f(3)=8
• 8 years agoHelpfull: Yes(1) No(0)
• f(-3)=81a-9b+2
  given that f(-3)=2
  s0,on equating we get
  81a-9b+2=2 =>9a=b
  then f(3)=81a-9b=8
  on substitutibg 9a=b we get
  f(3)=8.
• 10 years agoHelpfull: Yes(0) No(0)
• calculate f(-3) by substituting -3 in the fuction
  u will get something like this...
  81a-9b+2=2
  so 9a=b
  now substitute 3 in the function and use the above obtained relation
  u will get the answer as 8
• 10 years agoHelpfull: Yes(0) No(0)
• ans is 8
  
• 10 years agoHelpfull: Yes(0) No(0)
• f(-3)=a(-3)^4-b(-3)^2-3+5
  2=81a-9b+2
  81a-9b=0
  now,
  f(3)=81a-9b+3+5
  f(3)=0+8=8(bcoz we already know that 81a-9b=0)
• 10 years agoHelpfull: Yes(0) No(0)
• ans f(3)= 2+3=5
  
• 10 years agoHelpfull: Yes(0) No(1)
• f(-3)=81a-9b-3+5
  81a-9b+2=2
  81a-9b=0
  now,f(3)=81a-9b+3+5
  also from above 81a-9b=0
  so,f(3)=8
  
• 10 years agoHelpfull: Yes(0) No(0)
• f(-3)=2
  So, 81a+9b+2=2
  =>81a+9b=0
  f(3)=81+9b+8
  =0+8
  =8
• 10 years agoHelpfull: Yes(0) No(0)
• f(3)=8 is the ans.
  using f(-3) we get
  81a=9b
  now using this vlue in
  f(3)=81a-9b+3+5=0+3+5=8 is the ans
  
• 10 years agoHelpfull: Yes(0) No(0)
• f(x)=ax^4-bx^2+x+5.
  Now, replace x by -x, we get,
  f(-x)=ax^4-bx^2-x+5.
  Adding these two, we get,
  f(x)+f(-x)=2x
  Putting x=3, we get,
  f(3)+f(-3)=6
  =>f(3)=6+f(-3)
  =>f(3)=6+2
  =>f(3)=8
• 7 years agoHelpfull: Yes(0) No(0)
• f(-3)=2 and f(3)=?
  
  -3 -2 -1 0 1 2 3
  | | | | | | |
  2 3 4 5 6 7 8
• 6 years agoHelpfull: Yes(0) No(0)
• Here, f(-3)=2
  then, f(-2)=3
  f(-1)=4
  f(0)=5
  f(1)=6
  f(2)=7
  f(3)=8
• 6 years agoHelpfull: Yes(0) No(1)
• f(-3)=2 ----->a(-3)^4-b(-3)^2+(-3)+5
  f(3)=?------->a(3)^4-b(3)^2+(3)+5
  there is difference between -3^4 and 3^4
  and also -3^2 and 3^2
  so f(3)=2+3 ((-x)=-3)
• 6 years agoHelpfull: Yes(0) No(0)