In an examination of 26 marks, for correct question 5 marks are there, for wrong questions 8 marks are negative. A student scored zero marks. Actual marks he got before negating his marks is?

• its ans is 80
  in this ques .. he attempt all question so ...
  right ques is -- x
  wrong ques is -- 26-x
  so ..
  5x-(26-x)8=0
  13x=208
  x=16
  
  RIGHT ans is 16...
  Actual marks he got before negating his marks is-- 5*16 =80
  
• 9 years agoHelpfull: Yes(29) No(1)
• ANS:16 CORRECT QUESTION
  8 WRONG QUESTION
  26 MARKS
  5 MARK FOR CORRECT QUESTION
  8 FOR WRONG QUESTION
  10*8=80
  16*5=80
  16 CORRECT QUESTION
  8 WRONG QUESTION
  80-80=0
  
• 9 years agoHelpfull: Yes(10) No(6)
• 5x-8y=26 x is number of right ans and y is wrong ans. for him to get 0 5x=8y this happens when x=8 and y=5 so. marks when he answers right before negative is 40
• 9 years agoHelpfull: Yes(7) No(4)
• 80;
  'x' be wright answered and 'y' be wrong answered then 5x=8y;
  and x+y=26;
  solving both
  5x=80;
• 9 years agoHelpfull: Yes(5) No(0)
• Plz correct the q statement. "In an examination of 26 marks" means the full marks is 26.
• 9 years agoHelpfull: Yes(5) No(0)
• SORRY FOR PREVIOUS ANS..
  10 WRONG QUESTION..
• 9 years agoHelpfull: Yes(3) No(0)
• Given marks = 26
  for correct question 5 marks
  and for wrong = 8 marks
  so try to balance the marks because student scores zero marks
  now if he answered 8 correct questions marks are 8*5 =40 and now the wrong questions are 5*8=40 questions answered are 13 now total questions are 26 if we double the above questions 16*5=80 and to balance the marks 10*8=80
  therefore actual marks are 80
• 9 years agoHelpfull: Yes(3) No(1)
• Right answers x and wrong answers (26-x)
  Now, x*5 -(26-x)*8 = O
  x = 16
  so 16 Right answers and (26-16)=1O wrong answers.
  16*5 - 1O*8 =O
• 9 years agoHelpfull: Yes(3) No(0)
• wrong question 26 marks cant possible it should be total no of question=26 so answer=>5(x)-8(26-x)=0 solve x=16 so marks before negation=5x=80
• 9 years agoHelpfull: Yes(2) No(0)
• just take LCM of 5 and 8 i.e 40. so 40 marks he had scored before negating.
• 9 years agoHelpfull: Yes(1) No(1)
• Let the number of correct answer is x and number of incorrect answer is y
  So A.T.Q
  
  5x-8y=0 .........(i)
  
  As it is given that total marks is 26
  Then number of question must be asked (26/5)=5.2
  So sum of no of correct and incorrect answer will be 5.2
  Now we get 2 equation.
  
  5x-8y=0 and
  x+y=5.2 or 5x+5y=26 ...........(ii)
  
  Solving above 2 equation wet x=3.2 and y=2
  
  Then actual marks he got before negating is (3.2*5)=16 (Ans)
  
• 9 years agoHelpfull: Yes(1) No(0)
• from given solution total marks obtained in exam is 0
  so,5*x-8*(26-x)=0
  x=16 16 is the no of rright question
  so its marks will be 16*5=80
• 9 years agoHelpfull: Yes(1) No(0)
• 5x-(26-x)8=0
  on solving this we get x=16,means 16 correct ques.
  so,marks before negating is 16*5=80
• 9 years agoHelpfull: Yes(0) No(0)
• 40 well depends upon options too(the no divisible by 8 as well as 5)
• 9 years agoHelpfull: Yes(0) No(0)
• if 5 marks for rit ans.. then how can total marks b 26
  it should b multiple of 5
• 9 years agoHelpfull: Yes(0) No(0)
• the question is wrong. there are 26 questions and not 26 marks.
• 8 years agoHelpfull: Yes(0) No(0)
• 5x+8(x-26) = 0
  x=16
  Actual marks = 5*16=80
• 6 years agoHelpfull: Yes(0) No(0)