A ship went on a voyage after 180 miles a plane statrted with 10 times speed that of the ship.Find the distance when they meet from starting point.

a)179 miles
b)146 miles
c)200 miles

Answer is 200

• Ans c) 200 miles.
  
  
  Let the distance traveled by the ship after 180 miles to meet the plane be 'd'
  Speed of the ship be 'x' and speed of the ship be '10x'
  
  Time taken by plane to travel 180+d dist. = time take by ship for 'd' dist.
  (180+d)/10x=d/x
  180+d=10d
  d=180/9=20.
  
  So the distance traveled when they meet from starting point=180+d=200 miles
  
• 11 years agoHelpfull: Yes(4) No(1)
• let the time travelled aftr travelling 180m be t
  so the eqn becomes
  180+x*t=10*x*t
  solving we get xt=20
  and total distance travelled is 180+20=200m
  
• 11 years agoHelpfull: Yes(1) No(1)
• [Athira M. K.]
  Ans c) 200 miles.
  
  
  Let the distance traveled by the ship after 180 miles to meet the plane be 'd'
  Speed of the ship be 'x' and speed of the ship be '10x'
  
  Time taken by plane to travel 180+d dist. = time take by ship for 'd' dist.
  (180+d)/10x=d/x
  180+d=10d
  d=180/9=20.
  
  So the distance traveled when they meet from starting point=180+d=200 miles
• 11 years agoHelpfull: Yes(1) No(1)