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Numerical Ability
Age Problem
A , B, C works together and complete a work in 36 days. A and B can do the work same as twice of C, and A & C can do the work same as thrice of B. So in How many days C can do the work alone.
Read Solution (Total 19)
-
- A+B+C ONE DAY WORK = 1/36
C ONE DAY WORK = 1/X
A+B ONE DAY WORK = 2( C ONE DAY WORK) = 2/X
2/X+1/X=1/36
3/X=36
X=108
- 10 years agoHelpfull: Yes(38) No(0)
- Given
36(a+b+c) = 1
a+b = 2c
a+c = 3b
Equating the value;
36(2c+c) = 1
36(3c) = 1 --> c = 1/108
Hence c takes 108 days - 10 years agoHelpfull: Yes(14) No(0)
- 108. days.(a+b+c)1's work is 1/36.bt a+b=2c
so c's 1 day work is 3c=1/36
c=1/108.so total work done by c alone in 108 days
- 10 years agoHelpfull: Yes(4) No(0)
- a+b+c=1/36
also
1/a+1/b=2/c &
1/a+1/c=3/b
from solving eqn. 1 & 2 c=108 days - 10 years agoHelpfull: Yes(3) No(0)
- Given a+b+c=1/36
and a+b=2c;
a+c=3b therefore we can write a+b+c=1/36 as 2c+c=1/36
thereafter 3c=1/36
and c=1/108
C can do the work in 108 days - 10 years agoHelpfull: Yes(3) No(0)
- 1day'Work(A+B+c)=1/36
1day'Work(A+B)=1/36-1day'Work(c)
again,1day'Work(A+B)=2*1day'Work(c)
.'. 1/36-1day'Work(c)=2*1day'Work(c)
.'.3*1day'Work(c)=1/36
.'.1day'Work(c)=1/108
.'.108 day'Work(c)=1 - 10 years agoHelpfull: Yes(2) No(0)
- A+B+C=36,A+B=2C
so A=2C-B
subs. in 1st equ. for A
2C-B+B+C=36
3C=36
C=12,A=15,B=9
check:A+C=3B
15+12=3(9)
so C can do in 12 days - 10 years agoHelpfull: Yes(2) No(1)
- ANS 108
RIGHT I THINK WHAT ARE THE OPTIONS
- 10 years agoHelpfull: Yes(1) No(1)
- 108 totally right ans
- 10 years agoHelpfull: Yes(1) No(1)
- a+b+c=1/36
a+b=2c
a+c=3b
2c+c=1/36
c=1/108
c can do work in 108 days
- 10 years agoHelpfull: Yes(1) No(0)
- a+b+c=1/36
a+b=2c
a+c=3b
2c+c=1/36
c=1/108
hence c will do in 108 days - 10 years agoHelpfull: Yes(1) No(0)
- 108 days
a+b+c=1/36 where a=work done by the a in one day
a+b=2c
3c=1/36
c=1/108 - 10 years agoHelpfull: Yes(1) No(1)
- 1/a+1/b+1/c=1/36
2/c+1/c=1/36
C=36*3=108 - 10 years agoHelpfull: Yes(1) No(0)
- ans=12 a+b+c=36 a+b=2c,a+c=3b on solving it 2c+c=36 c=12
- 10 years agoHelpfull: Yes(1) No(1)
- a+b+c=36
3(a+b)=c
3(a+c)=b
on solving we get c=27 days
- 10 years agoHelpfull: Yes(1) No(1)
- A+B+C ONE DAY WORK=1/36.......... (1)
GIVEN THAT A+B=2C.............. (2)
PUT EQU.( 2) ON EQU. (1)
2C+C=1/36
BY SOLVING C=108 - 10 years agoHelpfull: Yes(1) No(0)
- c will do in 108days
- 10 years agoHelpfull: Yes(0) No(0)
- can u xplain how its ans is 108.
- 10 years agoHelpfull: Yes(0) No(2)
- 1 day work of A+B+C=1/36
A+B=2C
A+C=3B
1/36=3C
C=108 - 9 years agoHelpfull: Yes(0) No(0)
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