A man has some speed he crosses the square ground through diagonal in some min of time find the Area

4 km/h = 4,000/60 meters per minute
3 minutes at this speed = 12,000/60 = 200 meters
The diagonal of a square = (length of the side) x sqrt(2) . Length of the side = (diagonal)/sqrt(2)
Area = (side)2 = (diagonal)2/2 = (200)2/2 = 20,000 square meters
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Distance=speed*time
distance=sqrt(2)*a
area of square =a*a
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It may be..A man walking at the speed of 4 kmph crosses a square field diagonally in 3 minutes. The area of the field is:
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with speed and time you can calculate distance i.e diagonal length.
area= (diagonal)^2/2
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(vt)^2/2 is answer
let speed=v, time=t. then length of diagonal=vt.
side of square=vt/root(2). area of square=(vt/root(2))^2=answer
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Total work done
(A+B+C)36=1
also A+B=2C
so, (2C+C)*36=1
i.e 108C=1
so c C will complete wrk in 108 days
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speed given , time given, then distance can be calculated
and that is equal to diganol (d)
2x^2=d^2 (by pyhagorus)
x^2 is area which is = to d^2/2
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A man has some speed , he crosses the square ground through diagonal in some min of time. find the Area of Ground. I forgot the exact values of speed and time. But it was an easy one.