HOW+MUCH=POWER.Find the value of P+O+W+E+R.
a. 12 b.14
c. 16 d. 10

• a.12
  7 0 5
  9 8 3 7
  ------------
  1 0 5 4 2
• 9 years agoHelpfull: Yes(9) No(1)
• p+o+w+e+r = 77 =7+7=14 ans = 14
• 9 years agoHelpfull: Yes(7) No(7)
• How is a 3 digit number and Much is a 4 digit number and we got a 5 digit number. So left most digit is 1. (999 + 9999 = 19998).
  If you add two single digit numbers we get a maximum sum of 18. i.e., maximum carry over is 1. 1 + M = 10. So M = 9. and O = 0.
  Now the remaining digits available are 2, 3, 4, 5, 6, 7, 8.
  As O = 0, C + 1 = E, i.e., C and E are consecutive intezers. and E - C = 1
  Also, W + H = 10 + R ------(1), and H + U = 10 + W or H - W = 10 - U ------(2)
  Solving 1 and 2, we get 2H = 20 - (U - R)
  Now maximum value of U - R is 9. So 2H minimum value is 12, 14 etc as 2H is even.
  Say U - R = 8. only possible pairs are (9, 1), (8,0). Both are not possible as As M = 9 and O = 0.
  Say U - R = 6. Possible pairs are (9, 3), (8, 2), (7, 1), (6, 0). Only (8,2) possible.
  6 0 W
  9 8 C 7
  ------------
  105 E 2
  -----------
  As C and E are consequtive intezers, possible values for them are 3, 4. and W should take 5.
  7 0 5
  9 8 3 7
  ------------
  10 5 4 2
• 9 years agoHelpfull: Yes(6) No(1)
• cryptarithmetic logic------ P(1)+O(0)+W(5)+E(3)+R(1)
  total=1+0+5+3+1= 10
• 9 years agoHelpfull: Yes(2) No(3)
• How =705 and Much=9837 ...
  can any one explain it ?
• 9 years agoHelpfull: Yes(1) No(0)
• plzzzz.. someone expain the solution clearly i didn't understand..
• 9 years agoHelpfull: Yes(1) No(0)
• By trial and error MUCH=9837
  and HOW=705
  so POWER=10542
  1+0+5+4+2=12...
• 9 years agoHelpfull: Yes(1) No(2)
• power=77 and 7+7=14
• 9 years agoHelpfull: Yes(0) No(0)
• answer is 10 .
• 9 years agoHelpfull: Yes(0) No(1)
• @arun 4m wer did u get the values for p,o,w,e,r??
• 9 years agoHelpfull: Yes(0) No(0)
• please explain this cyrptography problemz..amo not understnading anything from dis..............i want the clear explanation.......please..........
• 9 years agoHelpfull: Yes(0) No(0)
• 12
  
  705+9837= 10542
• 9 years agoHelpfull: Yes(0) No(0)
• this is a cryptarithmetic problem. it can be solved using artificial intelligence method.
  by hit trial method, we will solve the equations
  first let assume P=1
  now, we see that if M assumed to be 9 and adding previous carry to it we get, we get 10 in which 1= P and 0=O.
  so three letters are solved i.e. P=1, M=9 and O=0.
  using these three we can solve other equations and find easily values of other remaining letters.
• 6 years agoHelpfull: Yes(0) No(1)