Two trains, Calcutta Mail and Bombay Mail, start at the same time from stations Calcutta & Bombay respectively towards each other. After passing each other, they take 12 hours and 3 hours to reach Bombay & Calcutta respectively. If the Calcutta Mail is moving at the speed of 48 km/h, the speed of the Bombay Mail is...
a) 24km/h
b) 22km/h
c) 21km/h
d) 96km/h
e) 120km/h

• cal mail speed:bombay mail speed is 48:x
  time ratio of two is 12:3
  cal speed/bombay speed=sqrt(bombay time)/sqrt(cal mail time)
  therefore,48/x=sqrt(3/12)
  bombay mail speed=2*48=96 km/hr
  thats the answer...............
• 10 years agoHelpfull: Yes(10) No(5)
• answer is c) 96 km/h
• 10 years agoHelpfull: Yes(3) No(8)
• formula
  calcutta train speed/mobay train speed=sqrt(3/12)
  the speed of bombay=96km/hr
• 10 years agoHelpfull: Yes(3) No(6)
• Time Ratio would be
  t/3=12/t where t= Time taken by each to reach meeting point
  hence t=6
  so time taken by each to reach meeting point is 6 hrs and 3 hrs hence speed ratio would be 1:2
• 8 years agoHelpfull: Yes(1) No(2)