three coins are tossed in the air at the sample time what are the chances that at least two of

ans is 50,no of chances are 4(TTH ,THT, TTT ,HTT).HENCE ANW IS 4/8=1/2=50
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the ans will be 50
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probability of tail coming atleast 2 times is 3/8 and pro. that tail coming 3 times is 1/8... hence 1/8+3/8=1/2=50
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3:50
t t t
t t h
t h t
h t t
there are 4 case of at least two of the coin has tails
total no of case=8
case are
ttt
tth
tht
thh
htt
hth
hht
hhh
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(1/2)*(1/2)*(1/2)+(1/2)*(1/2)*(1/2)+(1/2)*(1/2)*(1/2)
=3/8
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ans 50, total chance 8, 4/8=.50
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take success event is tail
probability of getting tail is p= 1/2
failure event head (q)=1/2
probability of getting tail at least two of three coins
(q+p)^r
here r=3
3c2 [(1/2)^2](1/2) +3c3 (1/2)^3=(1/2)=0.50
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Sample Set : HTT, THT, TTH, HHT,HTH,THH, HHH, TTT
Two Tails : HTT, THT, TTH
Probability: 3/8 (33.33)
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75
(1/2 x 1/2 x 1/2) x 3!
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50
HHH
HHT
HTH
HTT
THH
THT
TTH
TTT
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three coins are tossed in the air at the sample time .what are the chances that at least two of the coins will fall tails up?

1: 25
2: 33.33
3: 50
4: 75