the cost price of a cow and a horse is RS 3Lakhs. the cow is sold at 20% profit and the horse is sold at 10% loss. overall gain is rs 4200. what is the cost price of the cow ?

• Ans: Rs 114000
  Let cp of cow be x and horse be 300000-x
  sp of cow=(120/100)*x and sp of horse=(90/100)*(300000-x)
  Total sp= sp of cow + sp of horse
  Total cp= Rs 300000
  gain= Rs 4200
  Now atq,
  total sp - total cp= gain
  Find x and that is the solution.
• 10 years agoHelpfull: Yes(8) No(1)
• cow = 114000???
• 10 years agoHelpfull: Yes(3) No(0)
• overall profit=4200
  since sp-cp=4200
  sp-300000=4200=
  sp=304200
  let price of cow and horse is y
  x+y=3000000
  1.2x+.9y=304200
  by solving the eqns we get x=114000=cp of cow
• 10 years agoHelpfull: Yes(3) No(1)
• ans:1,14,000.
  let cp of cow =c and horse=h
  c+h=3,00,000 (given)-----(1)
  profit on cow is 20% i.e.c*20/100.and loss on horse is 10% i.e.h*10/100.
  overall profit is (2c-h)/10=4200----(2)
  slove 1 and 2
• 10 years agoHelpfull: Yes(2) No(0)
• ans is 10525
• 10 years agoHelpfull: Yes(1) No(3)
• c+h=3,00,000
  1.2c+0.9h=3,04,200
  by solving above two equations we get,
  c=2266
• 10 years agoHelpfull: Yes(1) No(1)
• OVERALL PROFIT %= 4200*100/300000=1.4%
  BY RULE OF ALLIGATION,
  DEARER-MEAN PRICE/MEAN PRICE-CHEAPER=RATIO
  10+1.4:20-1.4
  11.4:18.6
  114:18.6
  57:93
  COST OF COW=300000*57/150
  COST OF COW=114000
• 10 years agoHelpfull: Yes(1) No(0)
• Let x=cow,y=horse,
  x+y=300000
  1.2x+0.9y=304200
  
  By solving,
  x=114000 y=186000
• 10 years agoHelpfull: Yes(1) No(0)
• let price of cow is x and horse is y
  x+y=3,00,000
  1.2x+0.9y=3,04,200
  By Solving we get x=1,14,000 (y)
  
• 10 years agoHelpfull: Yes(1) No(1)
• 1.2c+0.9h=3.042*10^5
  c+h=3*10^5
  =>c=1140
• 10 years agoHelpfull: Yes(0) No(1)
• let cost price of cow and horse is x,y respectively
  then x+y=300000
  (.2x-.y)=(x+y)*100
  then x=
  y=
  
• 10 years agoHelpfull: Yes(0) No(0)
• n*1/5+n*1/10=4200+30000=34200
  so,n=342/3*1000=114000
• 10 years agoHelpfull: Yes(0) No(0)