A bag contains 8 white and 4 red balls.Five balls are drawn at random.What is the probability that two of them are red and 3 are white?

• five balls taken at random = 12C5
  probability of two red and 3 white = (4C2*8C3)/12C5 = 14/33
• 10 years agoHelpfull: Yes(64) No(1)
• p(event)=(number of event)/(total ways)
  8 white and 4 red=>total =12
  and event is to draw 5 balls from 12 balls(selection)
  =>total ways=12c5(read it as select 5 balls from 12 balls)=792
  now event is draw 2 red from 4 red balls(4c2=6) and 3 white balls from 8 white balls(8c3=56)
  so p(event)=(6*56)/(792)=14/33
  
• 10 years agoHelpfull: Yes(8) No(0)
• (4c2*8c3)/12c5=14/33
• 10 years agoHelpfull: Yes(3) No(0)
• 8C3*4C2/12C5=14/33
• 10 years agoHelpfull: Yes(3) No(0)
• (8c5 * 4c2)/12c5=14/33
• 10 years agoHelpfull: Yes(2) No(3)
• sample space=12c5
  events=8c3 * 4c2
  result=event/ss
• 10 years agoHelpfull: Yes(1) No(1)
• how ball can be drown: rrwww
  rwrwww
  rwwrw
  rwwwr
  wrwwr
  wwrwr
  wwwrr........
  so (4/12*3/11*8/10*7/9*6/8)*7=49/165
• 10 years agoHelpfull: Yes(1) No(8)
• 4c2*8c3/12c5
• 10 years agoHelpfull: Yes(1) No(0)
• (6*7*8)/6+(4*3)/2=62
• 10 years agoHelpfull: Yes(0) No(2)
• (8c3 * 4c2)/12c5 = 14/99
• 10 years agoHelpfull: Yes(0) No(1)
• (8c3)*(4c2)=336
• 10 years agoHelpfull: Yes(0) No(0)
• (8c3)*(4c2)=336
• 10 years agoHelpfull: Yes(0) No(0)
• ans is equals to 0.4242442
• 10 years agoHelpfull: Yes(0) No(1)
• 8c5*4c2=possibilities in which the balls are red and white.
  total no of possibilities are 12c5
  p=(8c5*4c2)/12c5
• 10 years agoHelpfull: Yes(0) No(0)
• selecting 2 balls as red then selection can be made in 4c2 ways...and selecting three balls as white from box can be done in 8c3 ways...thus the answer is 4c2*8c3/12c5
• 10 years agoHelpfull: Yes(0) No(0)
• (8c3*4c2)/12c5 and it also multiply by 2! becouse selection can be done in 2 ways so answer is (14/33)*2 = 28/33
• 10 years agoHelpfull: Yes(0) No(2)
• why haven't we multiplied it with 5! here ?
• 7 years agoHelpfull: Yes(0) No(0)