In an exam,it is required to get 65% of marks to pass.a stydent gets 874 marks and is declared failed by 10%marks.what is the maximum aggregate marks a student can get

• this is simple method:
  65% is the pass marks
  let me assume 100 is the max marks
  874 marks are declared to the failed of 10% marks
  so reduced to 65 to 55 percentage
  than 55 marks = 874
  100 =?
  874*(100/55)=1589.2
  100
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• 874+(10/100)*x=(65/100)*x
  which give x value as 1589.1
  which is the aggregate marks
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• approx aggregate is maximum 1590. which is full marks of the examination.
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• can u explain it ???
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• 65%of x=874+10%of x= 1589.1 approx
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