5 tables and 10 chairs were sold for 20000.15%gain for table,10%loss on chair.overall profit rs 750.the cp of table is

• Ans is 2140.
  let cost of table is X and chair is Y.
  sold price is 20000 and profit is 750 .
  so cost for both is 19250.
  then
  first eq is 5X+10Y=19250
  
  second eq is 5*(115/100)X + 10* (90/100)Y =20000
  
  solve both eqations , then get X=2140 (ans).
• 10 years agoHelpfull: Yes(76) No(3)
• overall cp=20000-750=19250
  let cost of tables=x
  (x*15/100)-(19250-x)*10/100=750
  x=10700
  cp of 1 table=10700/5=2140.
• 10 years agoHelpfull: Yes(16) No(4)
• CP OF TABLE=X
  CP OF CHAIR=Y
  SO 5 TABLE'S CP=100X/115
  SO 10 CHAIR'S CP=100Y/90
  SO, 115X/100 + 90Y/100 =20000
  AND X+Y =20000-750
  SO X=10700
  
• 10 years agoHelpfull: Yes(2) No(5)
• cp of table = 2200
  x+2y=4000
  1.15x+0.9(2y)=4150 (20750/5=4150)
  hence y=900 x=2200
• 10 years agoHelpfull: Yes(1) No(3)
• preethi wat u find is sp of 1 table. wat sudhakar mentioned is the correct answer.
• 10 years agoHelpfull: Yes(1) No(0)
• c.p of tables =x
  c.p of chairs =20000-x
  total s.p=(x*115/100)+((20000-x)*90/100)=20000
  x=8000
  the cp of the table is =8000/5=1600
• 10 years agoHelpfull: Yes(0) No(7)
• C.P of 5 tables = "x"
  C.P of 10 chairs ="y'
  total C.P =x+y =19250 ....1
  S.P = 115x/100+90y/100=20000.....2
  -90(1)+100(2)
  x=10700
  for each table =2140
• 7 years agoHelpfull: Yes(0) No(0)
• 15000
  5 percent = 750
  100 percent=?
• 6 years agoHelpfull: Yes(0) No(0)
• C.P of 5 tables = x
  C.P of 10 chairs =y
  total C.P =x+y =19250 1
  S.P = 115x/100+90y/100=20000 2
  -90(1)+100(2)
  x=10700
  for each table =2140
• 5 years agoHelpfull: Yes(0) No(0)