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jake writes all 4 digit no.s.
how many no. of 2's he write?
Read Solution (Total 9)
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- when the person use all the digits=9*10*10*10=9000
when the person not use 2 then all digits=8*9*9*9=5832
so when that person use 2 then=9000-5832=3168 - 10 years agoHelpfull: Yes(22) No(4)
- 1000+900*3=
3700 - 10 years agoHelpfull: Yes(8) No(3)
- (9*9*9)+(8*9*9)+(8*9*9)+(8*9*9)+2(9*9+8*9+8*9+9*9+8*9+9*9)+3(9+9+8+9)+4=
=2673+918+105+4=3700 - 10 years agoHelpfull: Yes(7) No(1)
- 9000-(8*9*9*9)=3168
- 10 years agoHelpfull: Yes(6) No(2)
- 9000-(8*9*9*9)=3168
- 10 years agoHelpfull: Yes(4) No(3)
- 10*10*10+3*9*10*10=3700
- 10 years agoHelpfull: Yes(3) No(0)
- 1000 to 1099 =19 no.s containing 2.
1100 to 1199 =19 no.s containing 2.
this is applicable to all but not in
2000 to 2999 they are 1000 no.s
hence
total no = 1000 + 19*80 = 2520 - 10 years agoHelpfull: Yes(1) No(3)
- explain clerly plz
- 10 years agoHelpfull: Yes(0) No(1)
- how they r saying 9000 as total 4 digit nos. there are 10,000 nos from 1000 to 9999
from 1000to1099=20
1100to1199=20
1200to1299=120
1300ti1399=20
.....n so on sooooo long..;) - 10 years agoHelpfull: Yes(0) No(0)
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