Let x,y and z be three sides of a triangle of a triangle of area m. Let w = 2(x + y + z). Then which of the following is true.

a.2m*m/w = (w/4-a)(w/4-b)(w/4-c) b. 4m*m/w = (w/4-a)(w/4-b)(w/4-c) c. b. 2m*m/w = (w/2-a)(w/2-b)(w/2-c)

• Correct ans is b. 4m*m/w = (w/4-a)(w/4-b)(w/4-c).
  
  You would had read the popular formula of area of triangle of sides a,b and c and with s = (a + b + c)/2 which is given by sqrt(s(s-a)(s-b)(s-c)).
  
  Now in our problem, a = x, b = y, and c = z. Also comparing w with s we can infer that s = w/4.
  
  Substituting these values in the original formula we get 4m*m/w = (w/4-a)(w/4-b)(w/4-c).
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