A boat M leaves shore A and at the same time boat B leaves shore B. They move across the river. They met at 500 yards away from A and after that they met 300 yards away from shore B without halting at shores. Find the distance between the shore A & B

• 1200 yards
  
  If X is the distance, a is speed of A and b is speed of B, then ;
  500/a= (x-500)/b and (x+300)/a = (2x-300)/b , solving it, we get x=1200 yards
• 13 years agoHelpfull: Yes(11) No(2)
• this is more liberal
  The boats first met after 500yards from A.
  Let the total distance between A and B be x.
  
  then,
  500/a = x-500/b,
  where, a = speed of A,
  b =speed of B.
  
  Assuming both boats are coming back to their original start place without halting at the shores,
  Distance coverred by A = x + 300
  Distance covered by B = 2x - 300
  
  x+300/a = 2x-300/b
  
  From above,
  500/x-500 = x+300/2x-300
  
  Solve, for x = 1200
• 10 years agoHelpfull: Yes(4) No(0)
• 1200 yds
• 13 years agoHelpfull: Yes(2) No(0)
• 1200 yards
• 13 years agoHelpfull: Yes(2) No(0)
• 1200 yards
• 13 years agoHelpfull: Yes(2) No(0)
• 1200 yards.
• 13 years agoHelpfull: Yes(1) No(1)
• 1200 yards
• 13 years agoHelpfull: Yes(0) No(0)
• if speed of boat u & v
  500/u =( x-500)/v ........(.1)
  (x-300)/u =300/v .....(2)
  x=800
  
• 8 years agoHelpfull: Yes(0) No(1)