A train normally covers a certain distance at a speed 60km/hr.however if it were to halt for a fixed time interval in each hour its avg speed reduced to 50km/hr what is the time interval for which the train halts in each hour

• stoppage time per hr = diff in speed / faster speed (hr)
  faster speed =60
  slower speed =50
  stoppage time = 10 / 60 hr = 1/6 hr = 10 min
• 10 years agoHelpfull: Yes(25) No(1)
• initial speed 60km/hr
  means it travel 60km in 1hr ,let x be halt time, now it will take (1+x)hr to travel 60km with speed of 50km/hr .... so 60/(1+x) = 50 means x = 1/5 hr = 12min halt time per hour...
• 10 years agoHelpfull: Yes(22) No(7)
• Since the train travels at 60km/hr,its speed per minute is 1km/min. hence if it travels at avg speed 50km/hr then it is travlling for 50 mins only, so time intrval per our is 10min
• 10 years agoHelpfull: Yes(4) No(0)
• @guru your ans is right....and formula is absolutely right
• 10 years agoHelpfull: Yes(4) No(4)
• Suppose distance = 300 (lcm of 50,60)
  time to cover in 60 kph= 5hrs
  time to cover in 50 kph= 6 hrs
  5 hour journey= 1 hour stoppage(extra time)
  1 ” ” = 1/5 hour stoppage =12 min.
  so, 12 mint stoppage per hour
  
• 10 years agoHelpfull: Yes(3) No(5)
• Train speed=60 km/hr.Means train cover 60 km in 1 hr.it cover 10 km in 10 min.
  But gven new distance cover in 60 min=50 km.So it takes 12 min to cover 10 km.after traveling for 10 min it take halt of 2 min.after 10 min it takes 2 min halt so after 60 min it takes 12 min halt.
  12 min halt will be after 60 min(1 hour).so it take only 10 min halt with in 60 min.
  
• 10 years agoHelpfull: Yes(2) No(0)
• sry guys , my ans is wrong . i found that formula in one blog, miss. aparna ans is right
• 10 years agoHelpfull: Yes(1) No(2)
• 10 min
  
  initial speed is 60 km/h
  reduced speed is 50 km/h
  
  dat makes it a difference of 1 hr and this difference is because of 60 km/h
  
  1 hr diff in 6hrs
  in 1 hr = 1/6 * 60 = 10 mins
• 10 years agoHelpfull: Yes(1) No(1)
• time of rest per hr=difference in avg speed/speed without stoppage
  60-50/60=10/60*60
  =10 minutes
• 10 years agoHelpfull: Yes(1) No(1)
• faster speed =60
  slower speed =50
  
  60-50=10
  
  now, (10/60)*60= 10
  Ans- 10 min
• 9 years agoHelpfull: Yes(1) No(0)
• http://www.examveda.com/a-train-cover-a-certain-distance-at-a-speed-of-60-kmhr-however-it-will-halt-for-fixed-time-interval-in-each-hour-its-average-speed-reduced-50-kmhr-what-179/
• 7 years agoHelpfull: Yes(1) No(0)
• (12/52)*(8/51)*(4/50)=answer.
• 10 years agoHelpfull: Yes(0) No(1)
• if a train speed s1 km/h and with a stopage speed s2 km/h then train stop of every hour is =(s1-s2)/s1
  = (60-50)/60
  =10/60
  =1/6 hours
  =60/6
  =10 min
• 9 years agoHelpfull: Yes(0) No(0)