TCS
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Numerical Ability
Arithmetic
AP GP HP Problem:
Given that x, y, z, p, q, r are all positive quantities, also xp, yq, zr are distinct.
If x,y and z are in A.P; p, q and r are in H.P. and xp, yq, zr are in G.P.; then calculate the value of x : y : z.
Answer is 1/r : 1/q : 1/p
Read Solution (Total 5)
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- in general if a,b,c,d are in AP then 1/a,1/b,1/c,1/d are all in HP.
so here 1/x,1/y,1/z are in HP.
1/x=p, x=1/p
1/y=q, y=1/q
1/z=r,z=1/r - 10 years agoHelpfull: Yes(15) No(3)
- when did you faced this question in TCS
- 10 years agoHelpfull: Yes(5) No(3)
- In general G^2=AH
(xp)^2=x*p
=> xp=1
=>x=1/p
similarly
y=1/q
z=1/r
so,x:y:z=1/p:1/q:1/r - 10 years agoHelpfull: Yes(5) No(2)
- (gp)^2= Ap*gp
xp^2= XP
x=1/p, aimilarl y=1/q and z=1/r - 10 years agoHelpfull: Yes(3) No(1)
- what is the correct solution?
- 10 years agoHelpfull: Yes(1) No(0)
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