Elitmus
Exam
Numerical Ability
Arithmetic
if the number of 2 rs, 5 rs and 10 rs coins are 500 and total sum of money is 3130.when the 5 rs and 10 rs coins are exchanged .total sum is decreased by 300.what are the no of coin of 2 rs .
option a 200 b 210 c 140
Read Solution (Total 5)
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- Ans is c.140
let number of coins of 2 rps are x.
Number of coins of 5 rps are y.
No.of coins of 10 rps are x.
Then
x+y+z=500-----------(1)
2x+5y+10z=3130----------(2)
2x+10y+5z=2830-----------(3)
solve (1),(2),and (3) you will get answer
140 coins of 2 rps
150 coins of 5 rps
210 of 10 rps coins - 10 years agoHelpfull: Yes(25) No(0)
- By using given options
140*2=280
so remaining coins are 500-140=360
given that if 5rs and 10rs coins are exchanged total sum decreases by 300
so the difference between 10rs and 5rs coins is 60(300/5)
now divide 360 in a way that difference between two numbers is 60
i.e, 210,150
210*10=2100
150*5=750
140*2=280
2100+750+280=3130
so ans is c)140 - 10 years agoHelpfull: Yes(0) No(0)
- x+y+z=500-----------(1)
2x+5y+10z=3130----------(2)
2x+10y+5z=2830-----------(3)
so number of Rs2 = 140 - 10 years agoHelpfull: Yes(0) No(0)
- c=140 where y=150,z=210,
3 eq are there
x+y+z=500
2x+5y+10z=3130
2x+5z+10y=2130
put x=500-y-z
and solve accordingly - 10 years agoHelpfull: Yes(0) No(0)
- ans s c-140
- 10 years agoHelpfull: Yes(0) No(0)
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