in how many ways can the number 2310 be expressed as a product of 3 factors.

• 2310=2*3*5*7*11
  two possibilities (as per question):
  grouping 3 factors at once => 5c3*1*1 (eg 30*7*11)= 10
  grouping 2 factors, 2 factors and 1 factor => 5c2*3c2*1 (eg 6*35*11) = 30
  
  so 30+10 = 40 ways !
• 9 years agoHelpfull: Yes(20) No(8)
• Ans is 243
  
  2310=11*7*3*5*2
  
  a=11^p1*7^q1*3^r1*5^s1*2^t1.
  B=11^p2*7^q2*3^r2*5^s2*2^t2.
  C=11^p3*7^q3*3^r3*5^s3*2^t3.
  Where a*b*c=2310 and
  p1+p2+p3=1
  q1+q2+q3=1
  r1+r2+r3=1
  s1+s2+s3=1
  t1+t2+t3=1
  
  So 3*3*3*3*3=243
• 9 years agoHelpfull: Yes(10) No(21)
• We have 2310 = 2*3*5*7*11
  
  Say 2310 = _ * _ * _
  
  Now, each number can go at 3 places. So, we will get 3^5 i.e. 243 ways.
  
  But, 2310*1*1, 1*2310*1 and 1*1*2310 are same. So, we need to remove 2 cases out of 3 here. Out of remaining 240 cases, we need to consider 240/(3!) i.e. 40 cases.
  
  So, total should be 41.
• 9 years agoHelpfull: Yes(9) No(1)
• {3 Factors}*{1 Factor}*{ 1 Factor}
  or {2 Factors}*{2 Factors}*{ 1 Factor}
  
  5c3 + 5c2*3c2 = 40
• 9 years agoHelpfull: Yes(8) No(0)
• 41 is the correct ans
  http://www.pagalguy.com/cat/official-quant-thread-for-cat-2011-part-4-25070678/6543045
• 9 years agoHelpfull: Yes(3) No(0)
• ans 5C3 = 10
• 9 years agoHelpfull: Yes(2) No(6)
• We have 2310 = 2*3*5*7*11
  
  Say 2310 = _ * _ * _
  
  Now, each number can go at 3 places. So, we will get 3^5 i.e. 243 ways.
  
  But, 2310*1*1, 1*2310*1 and 1*1*2310 are same. So, we need to remove 2 cases out of 3 here. Out of remaining 240 cases, we need to consider 240/(3!) i.e. 40 cases.
  
  So, total should be 41.
• 9 years agoHelpfull: Yes(2) No(0)
• The correct must be 41..
• 9 years agoHelpfull: Yes(1) No(0)
• 2310 = 2*3*5*7*11
  When a number can be expressed as a product of n distinct primes,
  then it can be expressed as a product of 3 numbers in (3^(n-1) + 1)/2 ways=41 ways
  
• 9 years agoHelpfull: Yes(1) No(0)
• THIS SITE SUCKS IN SOLUTIONS!!!!
• 9 years agoHelpfull: Yes(1) No(1)
• num of ways= 3*3!=18
• 9 years agoHelpfull: Yes(0) No(1)
• ans:18
  sol:3*3*2*1=18
• 9 years agoHelpfull: Yes(0) No(5)
• 4
  
  ans:4c3
• 9 years agoHelpfull: Yes(0) No(1)
• Ans 15. If valus of factors are not same.
  5c1+5c2=5+10=15
• 9 years agoHelpfull: Yes(0) No(5)
• 5C3 ways
  =10
• 9 years agoHelpfull: Yes(0) No(2)
• 2310 = 2*3*5*7*11....
  A product of 1st 5 prime numbers... 5 Factors!
  
  
  U need to take the product of 3 factors out of these 5 factors....
  Which can be taken in two ways.....
  {1 Factor}*{1 Factor}*{the rest 3 Factors}
  or {1 Factor}*{2 Factors}*{the rest 2 Factors}
  
  1st Case: There are 5*4 ways = 20 Ways
  2nd Case: There are 5*6(4C2) ways = 30 Ways
  
  A total of 50 ways in which 2310 can be expressed as a product of three factors....
• 9 years agoHelpfull: Yes(0) No(5)
• how can you write 5*4,5*4(6c2)ways Mr.aditya
• 9 years agoHelpfull: Yes(0) No(2)
• 2310=2*3*5*7*11;
  mulitple of three=(2*3)(5*7)(11)
  (2*3)(5*11)(7);
  like this for other number so..30 ways...
• 9 years agoHelpfull: Yes(0) No(1)
• 2310=2*3*5*7*11
  here is two conditions if we club these factors in to multiple of three factors.that are 2.2.1 and 1.1.3
  number of ways =(5c2.4c2.1)+(5c1.4c1.3)=120
• 9 years agoHelpfull: Yes(0) No(4)
• correct ans =14
  
  
• 9 years agoHelpfull: Yes(0) No(1)
• can anyone tell me what is the correct solution for this ????
• 9 years agoHelpfull: Yes(0) No(0)
• 2310=_*_*_ each have 5 choices so 5^3
  that cant be true
  bcz it makes 2310=2*3*5 or any case n which is not true
• 9 years agoHelpfull: Yes(0) No(0)
• 2310=2*3*5*5*11
  then total possible ways for expressed 2301 as a multiple of three numbers is 4p3=24
• 8 years agoHelpfull: Yes(0) No(0)