Elitmus
Exam
Numerical Ability
Probability
Ram has three pyramidal dice numbered as 1,2,3,4 what is the probability that on throw of dice simultaneously the sum of number appeared on it is a prine number
Read Solution (Total 17)
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- ans-22/64
Explanation:-
2,3,5,7,11 primes
for 2 no any possibility
for 3
1+1+1=3 (1 way)
for 5
1+2+2=5 (3 way)
1+1+3=5 (3 way)
for 7
1+2+4=7 (6 way)
1+3+3=7 (3 way)
1+3+3=7 (3 way)
2+2+3=7 (3 way)
for 11
3+4+4=11 (3 way)
total no of ways=64
total event occurred is 22
therefore probability = 22/64
- 10 years agoHelpfull: Yes(30) No(7)
- 19/64;
1 1 1- 1 way,
1 2 2- 3 ways,
1 1 3- 3 ways,
1 2 4- 6 ways,
1 3 3- 3 ways,
3 4 4- 3 ways,
19/64 Ans... - 10 years agoHelpfull: Yes(20) No(15)
rigth ans-22/64
Explanation:-
2,3,5,7,11 primes
for 2 no any possibility
for 3
1,1,1=3 (1 way)
for 5
1,2,2=5 (3 way)
1,1,3=5 (3 way)
for 7
1,2,4=7 (6 way)
1,3,3=7 (3 way)
2,2,3=7 (3 way)
for 11
3,4,4=11 (3 way)
total no of ways=64
total event occurred is 22
therefore probability = 22/64- 10 years agoHelpfull: Yes(17) No(0)
- sum of numbers appearing on the face when three pyramidal dice is thrown simultaneously are 3, 5, 7, 11.
(1,1,1);sum=3, 1 event.
(2,2,1);sum=5, 3 events.
(3,1,1);sum=5, 3 events.
(5,1,1);sum=7, 3 events.
(4,2,1);sum=7, 3 events.
(3,3,1);sum=7, 3 events.
(4,4,3);sum=11, 3 events.
so,total number of favourable events=19.
total number of events=4^3=64.
therefore , probability=19/64. - 10 years agoHelpfull: Yes(9) No(8)
- 1/4....
At 1--> 2+3+4= 9 not prime
At 2 - - > 1+3+4=8 not prime
At 3 - - > 1+2+4= 7 is PRIME
At 4, - - > 1+2+3= 6 not prime
So probability 1/4
According to options 16/64 as far as I remember - 10 years agoHelpfull: Yes(6) No(3)
- for 7 12 chances for all prime numbrs 10 chances so 22/64
- 10 years agoHelpfull: Yes(4) No(0)
- 22/64 or 11/32 is the correct answer
- 10 years agoHelpfull: Yes(3) No(2)
- (1,1,1)- 1
(1,2,4)- 31!=6
(3,3,1)- 3
(4,4,3)- 3
(2,2,1)- 3
(1,1,3)- 3
Total- 19
Therefore, Probability= 19/(4)^3 = 19/64
- 10 years agoHelpfull: Yes(3) No(2)
- (1,1,1)=1 way
(1,2,2)=3 ways
(1,3,3)=3 ways
(1,2,4)=6 ways
so probability=13/64 - 10 years agoHelpfull: Yes(2) No(2)
- ans 22/64
111=3(1 way)
122=5(3 ways)
113=5(3 ways)
124=7(6 ways)
133=7(3 ways)
223=7(3 ways)
443=11(3ways)
p=22/64 - 10 years agoHelpfull: Yes(2) No(1)
- 3!+3!/2+3!/2=12
- 10 years agoHelpfull: Yes(1) No(1)
- ans-4/16=1/4
- 10 years agoHelpfull: Yes(1) No(2)
- @SUBHAJIT DHIBAR 7 is also done by (3,2,2)which has 3 ways...is it wright or wrong???plz me me
- 10 years agoHelpfull: Yes(1) No(0)
- right ans is 19/64.
- 10 years agoHelpfull: Yes(1) No(1)
- for 3
1+1+1=3(1 way)
for 5
1+2+2=5(3 ways)
1+1+3=5(3 ways)
for 7
1+1+5=7(3 ways)
1+2+4=7(6 ways)
1+3+3=7(3 ways)
2+2+3=7(3 ways)
for 11
3+4+4=11(3ways)
no. of ways for prime no.(E)=1+3+3+3+6+3+3+3=25
total no. of ways(S)=4*4*4=64
Therefore, probability=E/S=25/64
- 9 years agoHelpfull: Yes(1) No(1)
- ans is 19/4
- 10 years agoHelpfull: Yes(0) No(1)
- 4 is not a prme no guyz
- 10 years agoHelpfull: Yes(0) No(0)
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