A,B,C are having some marbles with each of them.
A has given B and C the same number of marbles each of them already have.
Then, B gave C and A the same number of marbles they already have.
Then C gave A and B the same number of marbles they already have.
At the end A, B, and C have equal number of marbles.
11. If x,y,z are the marbles initially with A,B,C respectively,
then the number of marbles B has at the end are ____
1] 2(x-y-z) 2] 4(x-y-z) 3] 2(3y-x-z)
4] x + y-z
12. If the total number of marbles are 72, then the number of marbles with A at the starting were
1] 20 2] 30
3] 32 4] 39

• Answers 2(3y-x-z),, 39
  11)question
  given that three numbers are x,y,z
  first A given to B,C
  so B=2y
  C=2z
  A=x-y-z
  second B gives C,A
  C=4z
  A=2(x-y-z)
  B=3y-z-x
  third C gives A,B
  A=4(x-y-z)
  B=2(3y-z-x)
  C=5z-x-3y
  so ans is 2(3y-z-x)
  
  question 12
  at final A,B,C Same numers
  so 4x-4y-4z=72/3=24-------(1)
  x+y+z=72----------(2)
  solve (1) and (2)
  A at starting has 39
  
  
  
• 9 years agoHelpfull: Yes(3) No(0)
• Answers 2(3y-x-z),, 39
  11)question
  given that three numbers are x,y,z
  first A given to B,C
  so B=2y
  C=2z
  A=x-y-z
  second B gives C,A
  C=4z
  A=2(x-y-z)
  B=3y-z-x
  third C gives A,B
  A=4(x-y-z)
  B=2(3y-z-x)
  C=5z-x-3y
  so ans is 2(3y-z-x)
  
  question 12
  at final A,B,C Same numers
  so 4x-4y-4z=72/3=24-------(1)
  x+y+z=72----------(2)
  solve (1) and (2)
  A at starting has 39
  
  
  
• 9 years agoHelpfull: Yes(1) No(1)
• Answers 2(3y-x-z),, 39
  11)question
  given that three numbers are x,y,z
  first A given to B,C
  so B=2y
  C=2z
  A=x-y-z
  second B gives C,A
  C=4z
  A=2(x-y-z)
  B=3y-z-x
  third C gives A,B
  A=4(x-y-z)
  B=2(3y-z-x)
  C=5z-x-3y
  so ans is 2(3y-z-x)
  
  question 12
  at final A,B,C Same numers
  so 4x-4y-4z=72/3=24-------(1)
  x+y+z=72----------(2)
  solve (1) and (2)
  A at starting has 39
  
• 9 years agoHelpfull: Yes(1) No(0)