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Exam
Numerical Ability
find remainder when (n^2+n+41)^2 is divided by 12
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- ans is 1
first put n=1...we get1849/12.remainder will be 1...again put n=2...we get2209/12...remainder will be again put n=3,4,5...the last term of numerator will be always 9...if they divide by 12 we always get 1 remainder
- 9 years agoHelpfull: Yes(1) No(0)
- Ans is 6
Take n=1 - 9 years agoHelpfull: Yes(0) No(2)
- Answer to this question is 6.
- 9 years agoHelpfull: Yes(0) No(1)
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