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Exam
Numerical Ability
Number System
find number of zeroes at end of 1!*2!*3!*.........*30!
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- Ans is 87 zeros
for 5! to 9! One zero for each
1+1+1+1+1=5
from 10! To 14 fact two zeros
2+2+2+2+2=10
for 15 to 19 fact three zeros
3+3+3+3+3=15
from 20 fact to 24 fact 4 zeros each 4*5=20
from 25 to 29 fact 6 zeros
6*5=30
for 30 fact there are 7 zeros
so total zeros=5+10+15+20+30+7=87 zeros - 10 years agoHelpfull: Yes(5) No(0)
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