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Exam
Numerical Ability
Sequence and Series
51,100,121,144,202,? next term
Read Solution (Total 1)
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- next term will be 289
7*7+2=51
10*10=100
11*11=121
12*12=144
14*14+6=196
here after 7 on the gap of three there 3 perfect square
and after having three consecutive perfect square,next term is
multiple of 7 plus 6(i.e on the difference of 4,from 1st multiple of 7)
so next term will be again at difference of 3
i.e 17*17=289
18*18=324
19*19=326
21*21+10=451
so series will be 51,100,121,144,202,289,324..... - 10 years agoHelpfull: Yes(0) No(0)
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