Four people each roll a die once. Find the probability that at least two people will roll the same number?

• atleast 2 means
  1-p(no one has same number)
  p(no person has same number)=6*5*4*3/6^4=10/36
  reqd probability=1-10/36
  =26/36=13/18
  
  
• 10 years agoHelpfull: Yes(23) No(6)
• For at least 2 there will be 3 cases
  case 1 : 2 people having same number on dice 1/6*1/6*5/6*5/6,
  as these 4 can be arranged in 4P2 ways net probability is 150/6^4
  case 2 : 3 people having same number on dice, we get 20/6^4
  case 3 : 4 people having same number , 1/6^4
  hence ans is 171/6^4 or (4P2+4P3+4P4)/6^4
• 10 years agoHelpfull: Yes(4) No(6)
• 4c2+4c3+4c4/6^4
• 10 years agoHelpfull: Yes(4) No(4)
• Two are same: 4c2
  Three are same: 4c3
  all Four are same: 4c4
  Total chances: 6^4
  so;
  4c2+4c3+4c4/6^4
• 10 years agoHelpfull: Yes(3) No(7)
• total ways-no of ways when all nos are different=no of ways when atleast two people have same no
  so this will be=
  6c1*6c1*6c1*6c1 - 6c1*5c1*4c1*3c1
  probability= this expression divided by total ways
  ans= 6c1*6c1*6c1*6c1 - 6c1*5c1*4c1*3c1 / 6c1*6c1*6c1*6c1 = 13/18
• 10 years agoHelpfull: Yes(1) No(1)