What is the 100th term of the series 2 4 8 14 22

given 2,4,8,14,22 we can write the series as 2,2+2,2+3+3,2+4+4+4,2+5+5+5+5,...
so 100th term contains 2+100+100+100+...........99terms
2+9900=9902
ans:9902
10 years agoHelpfull: Yes(9) No(0)
a(100)=a+n(n-1)
a(100)=2+100(100-1)
9902 this is final ans
10 years agoHelpfull: Yes(7) No(6)
Tn=2+n(n+1)
for n=0
T0=2
T1=4
T2=8
T3=14
so 100th term
T99=2+99(99+1)=2+9900=9902
10 years agoHelpfull: Yes(2) No(0)
100th term is 9902
2,4,8,14,22....
see the difference between the terms is an ap with a=2 and c.d=2
2,4,6,8....
an=sum of n-1 terms and the first term of the above series
a100=s99of a.p +2
S99=99/2(4+196)=9900
a100=9900+2=9902
10 years agoHelpfull: Yes(1) No(0)
The given series is in A.P & the formula to find the 100th term is
Tn=a+(n-1)d
here,
a=2
d=2
n=100
By sub above value u will get
ans:200
10 years agoHelpfull: Yes(0) No(17)
n*(n+2)/2
where n is 100.
100*51=5100
10 years agoHelpfull: Yes(0) No(9)
a(n+1)=a^2+a+2
a(0+1)=1^2+0+2=2
a(1+1)=1^2+1+2=4
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.
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a(99+1)=99^2+99+2=9902
10 years agoHelpfull: Yes(0) No(0)
difference between consecutives are multiple of 2.
so 32
10 years agoHelpfull: Yes(0) No(4)
nth term of this series(tn)=n^2 -(n-2)

hence,100th term=100^2 -98 =9902
10 years agoHelpfull: Yes(0) No(0)
this is in the form
the every N th number is (N-1)*N+2
for 1st number apply above formula
1st number=0*1+2=2
2nd number=1*2+2=4
3rd number=2*3+2=8
4th number=3*4+2=14
5th number=4*5+2=22
so 100 th number will be
99*100+2=9902.
9 years agoHelpfull: Yes(0) No(0)

What is the 100th term of the series 2,4,8,14,22?