What is the 100th term of the series 2,4,8,14,22?

• Ans is 9902
  this is in the form
  the every N th number is (N-1)*N+2
  for 1st numner aplly above formula
  1st number=0*1+2=2
  2nd number=1*2+2=4
  3rd number=2*3+2=8
  4th number=3*4+2=14
  5th number=4*5+2=22
  so 100 th number will be
  99*100+2=9902.
• 9 years agoHelpfull: Yes(36) No(0)
• given 2,4,8,14,22 we can write the series as 2,2+2,2+3+3,2+4+4+4,2+5+5+5+5,...
  so 100th term contains 2+100+100+100+...........99terms
  2+9900=9902
  ans:9902
• 9 years agoHelpfull: Yes(9) No(0)
• a(100)=a+n(n-1)
  a(100)=2+100(100-1)
  9902 this is final ans
• 9 years agoHelpfull: Yes(7) No(6)
• Tn=2+n(n+1)
  for n=0
  T0=2
  T1=4
  T2=8
  T3=14
  so 100th term
  T99=2+99(99+1)=2+9900=9902
• 9 years agoHelpfull: Yes(2) No(0)
• 100th term is 9902
  2,4,8,14,22....
  see the difference between the terms is an ap with a=2 and c.d=2
  2,4,6,8....
  an=sum of n-1 terms and the first term of the above series
  a100=s99of a.p +2
  S99=99/2(4+196)=9900
  a100=9900+2=9902
• 9 years agoHelpfull: Yes(1) No(0)
• The given series is in A.P & the formula to find the 100th term is
  Tn=a+(n-1)d
  here,
  a=2
  d=2
  n=100
  By sub above value u will get
  ans:200
• 9 years agoHelpfull: Yes(0) No(17)
• n*(n+2)/2
  where n is 100.
  100*51=5100
• 9 years agoHelpfull: Yes(0) No(9)
• a(n+1)=a^2+a+2
  a(0+1)=1^2+0+2=2
  a(1+1)=1^2+1+2=4
  .
  .
  .
  .
  a(99+1)=99^2+99+2=9902
• 9 years agoHelpfull: Yes(0) No(0)
• difference between consecutives are multiple of 2.
  so 32
• 9 years agoHelpfull: Yes(0) No(4)
• nth term of this series(tn)=n^2 -(n-2)
  
  hence,100th term=100^2 -98 =9902
• 9 years agoHelpfull: Yes(0) No(0)
• this is in the form
  the every N th number is (N-1)*N+2
  for 1st number apply above formula
  1st number=0*1+2=2
  2nd number=1*2+2=4
  3rd number=2*3+2=8
  4th number=3*4+2=14
  5th number=4*5+2=22
  so 100 th number will be
  99*100+2=9902.
  
• 8 years agoHelpfull: Yes(0) No(0)