w,x,y,z are non negative integer each less than A, w(3^3) + x(3^2) +y(3) +z=117, if A=3 the no of solution is 1, what will be the no of solutions when A=4.
A)6
B)5
C)4
D)3

• wrong question ,for a=3 threr will be no soln ,
  because for max value of w,x ,y ,z that is 2 ,sum < 117
  
  but for a=4 there will be 1 soln ,when w=x=y=3 and z=0,
  
  for a=5
  w=x=y=3,z=0
  w=4,x=0,y=3,z=0
  w=3,x=4,y=z=0
  
  so for a=5 ans should be d)3
  
  if in question it is given that each less then equal to a instead of less then a
  then for a=4 ans will be d)3
  
  
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