find the sum of 24 terms of an arithmetic progression if a1+a5+a10+a15+a20+a24 is225

• there is a property in AP
  i,e (1st term + last term) = ( 2nd term + 2nd last term ) and so on
  so we can write (a1+a24)=(a5+a20)=(a10+a20)
  => a1+a24 = 225/3 = 75
  sum of 24 terms = (24/2) (a1+a24) = 12*75 = 900
• 10 years agoHelpfull: Yes(3) No(0)