The price of a commodity (in rupees per kg) is 100 + 0.1n, on the nth day of 2007(n=1,2,3....100) and then remains constant . on the other hand the price of another commodity( in rupees per kg) is 89 + 0.15n , on the nth day of 2007( n=1,2,3,...365). On which date on 2007 will the price of these two commodities be equal?

• after 100th day it become const so max value for 1st eq. 100+.1*100 =110
  110= 89+.15n
  n=140
  jan =31
  and so onn.. 28,31,30
  ans 20 may
• 9 years agoHelpfull: Yes(32) No(3)
• 110=89+0.15n
  n=140
  May 20
• 9 years agoHelpfull: Yes(6) No(3)
• 100+0.1n=89+0.15n
  100-89=0.15n-0.1n
  0.05n=11
  n=11/0.05=11*100/5=220
  hence 220th day price of two commodities equal
  July 29 is 220th day
  
  proof:
  100+0.1(220)=89+0.15(220)
  100+22=89+33
  122=122
• 9 years agoHelpfull: Yes(6) No(17)
• At the 100 the day the value of 1st commodity is 110 and 2nd commodity is 104.
  
  So the eqn becomes
  89+0.15n=110
  =>.15n=110-89
  =>n=140
  
  So the total day is 100+140=240
  The 243rd day is 31st July
  240 th day becomes 28th July.
• 9 years agoHelpfull: Yes(2) No(0)
• explain in proper way so that we can understand
• 9 years agoHelpfull: Yes(1) No(0)
• After 100 day 1st commodity becomes
  100+0.1*100=110
  and second commodity becomes
  89+0.15*100=104.
  It means need more than 100 day to be a equal but 1st commodity constant after 100 day so equation becomes as
  89+0.15n=110
  after solving we get n=140day
  140day/30 =4 month 20 days
  so the day is 20 may.
• 9 years agoHelpfull: Yes(1) No(0)
• plz explain
• 9 years agoHelpfull: Yes(0) No(1)