TCS
Company
Numerical Ability
Sequence and Series
what will be the 9th & 99th number of the following series:
2, 10, 26, 50........................
Read Solution (Total 5)
-
- if we observe pattern
2nd number is (8*1)+2
3rd number is (8*2)+(8*1)+2
4th number is (8*3)+(8*2)+(8*1)+2
hence 9th number is (8*8)+(8*7)+...+(8*2)+(8*1)+2
=8(8+7+6+5+4+3+2+1)+2
=8((8*9)/2)+2 (sum of n numbers)
=288+2
=290
99th number is (8*98)+(8*97)+(8*96)+...+(8*2)+(8*1)+2
=8(98+97+96+...+2+1)+2
=8((98*97)/2)+2
=38808+2
=38810
9th number is 290 & 99th number is 38810 - 10 years agoHelpfull: Yes(36) No(4)
- This is in the form
1^2+1,,3 ^2,,5^2+1,,7^2+1
so 9th number will be 17^2+1
and 99th number is =197^2+1 - 10 years agoHelpfull: Yes(19) No(0)
- Is form a quadratic eqn ax^2 +bx + c =tn
Implies a+b+c=2
4a+2b+c=10
9a+3b+c=26
Solving u get a 4 b -4 and c 2
Eqn bcm 4x^2-4x+2
Put x 9 for ninth term .it will be 290 - 10 years agoHelpfull: Yes(1) No(1)
- 290 for 9th term
i.e
9*2=18-1=17=17*17+1=289+1=290
now
99*2=198-1=197
197*197+1
- 10 years agoHelpfull: Yes(0) No(0)
- t9=2+(9-1)*8=66
t99=2+(99-1)*8=786 - 4 years agoHelpfull: Yes(0) No(0)
TCS Other Question