#include
int a[5] ={1,2,3,4,5},i,j=2,b;
func(int j,int *a)
{
j=j+1;
a=a+j;
b= b+2;
}
int main()
{
for (i =0;i<5;i++ )
func(j,a[i]);
for (i =0;i<5;i++ )
printf("%d",a[i]);
return 0;
}

• 12345
  its only a code to print the array a[5], everything else this is only a distraction
• 9 years agoHelpfull: Yes(27) No(6)
• compiler error a[i] is integer cannot be stored in pointer
• 9 years agoHelpfull: Yes(8) No(3)
• [Error] invalid conversion from 'int' to 'int*' in func(j,a[i])
• 8 years agoHelpfull: Yes(4) No(1)
• output: a[0]=4
  a[1]=5,
  a[2]=6,
  a[3]=7,
  a[4]=8
• 9 years agoHelpfull: Yes(1) No(11)
• 12345 because function is nor reurning anythng ..it simply prints elemnts of an array
  
• 9 years agoHelpfull: Yes(0) No(3)
• ERROR
  because we require a pointer array for this scenario.
• 8 years agoHelpfull: Yes(0) No(0)
• from integer to pointer conversion is by default... so no error and will print 1,2,3,4,5
• 7 years agoHelpfull: Yes(0) No(0)
• output of this question is- 1 2 3 4 5
• 7 years agoHelpfull: Yes(0) No(1)
• output is: 12345
• 7 years agoHelpfull: Yes(0) No(0)
• output will be 12345
• 6 years agoHelpfull: Yes(0) No(0)