include int a 5 1 2 3 4 5 i j 2 b func int j int a j j

12345
its only a code to print the array a[5], everything else this is only a distraction
10 years agoHelpfull: Yes(27) No(6)

compiler error a[i] is integer cannot be stored in pointer
10 years agoHelpfull: Yes(8) No(3)
[Error] invalid conversion from 'int' to 'int*' in func(j,a[i])
9 years agoHelpfull: Yes(4) No(1)
output: a[0]=4
a[1]=5,
a[2]=6,
a[3]=7,
a[4]=8
10 years agoHelpfull: Yes(1) No(11)
12345 because function is nor reurning anythng ..it simply prints elemnts of an array
9 years agoHelpfull: Yes(0) No(3)
ERROR
because we require a pointer array for this scenario.
9 years agoHelpfull: Yes(0) No(0)
from integer to pointer conversion is by default... so no error and will print 1,2,3,4,5
8 years agoHelpfull: Yes(0) No(0)
output of this question is- 1 2 3 4 5
8 years agoHelpfull: Yes(0) No(1)
output is: 12345
7 years agoHelpfull: Yes(0) No(0)
output will be 12345
7 years agoHelpfull: Yes(0) No(0)

#include
int a[5] ={1,2,3,4,5},i,j=2,b;
func(int j,int *a)
{
j=j+1;
a=a+j;
b= b+2;
}
int main()
{
for (i =0;i<5;i++ )
func(j,a[i]);
for (i =0;i<5;i++ )
printf("%d",a[i]);
return 0;
}