two ants start simultaneosly from two ant holes towards each other.the first ant covers 8%of the distance between the two ant holes in 3 hrs,the second ant covered 7/120 of the distance in 2 hrs 30 minutes.Find the speed (feet/hr) of the second ant if the first ant travelled 800 feet to the meeting point?

• 21 ft/hr
  calculate individual speed of ants
  soant1=2x/75
  aoant2=7x/300
  where x is the distance in feet
  time taken by ant 1 to cover 800ft=800/(2x/75)
  speed of 2nd ant=(x-800)/(2x/75)/800
  equate with soeed of 2nd ant explained above
  
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