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How many boys are there in the class?
The number of boys in the class is 8 more than the number of girls in the class, which is five times the difference between the number of girls and boys in the class.
Read Solution (Total 13)
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- eqn;
8+y=5(x-y); y=no of girlz & x=boys
so, y=32 & x=8+y ie 40
40 ans. - 10 years agoHelpfull: Yes(15) No(4)
- let no.of boys is x nd girls y
now as per qsn x-y=8
nw, y=5(x-y)
so, y=5*8=40
so no. of girls 40;
no of boys 48 - 10 years agoHelpfull: Yes(12) No(8)
- answer is 40
suppose let x+8 be the total no.of boys and y be the no.of girls
x-y=8
and x+8=5(x-y)
=5(8)
=40
there fore total no.of boys are 40
- 10 years agoHelpfull: Yes(6) No(3)
- 8+y=5(x-y)
8+y=5x-5y, 5x-6y=8....(1)
x-y=8...(2)
we get y=32(no of girls)
x=40 - 10 years agoHelpfull: Yes(6) No(0)
- 48 is correct ans...
- 10 years agoHelpfull: Yes(4) No(6)
- B-8=G......(1)
G=5(B-G).....(2)
From eqn 1 & 2 we got B=48 - 10 years agoHelpfull: Yes(3) No(5)
- correct ans >>>>>is 48.
- 10 years agoHelpfull: Yes(3) No(3)
- No. of boys will be 40.
- 10 years agoHelpfull: Yes(2) No(1)
- Boys = 8 + girls
8 + girls = 5((8+ girls )-girls)
girls=40-8=32
boys=8+girls=8+32=40
- 10 years agoHelpfull: Yes(2) No(0)
- no. of girls= x, no. of boys= x+8, diff b/w boys and girls =8,
x+8 =5(8), x=32, no. of boys = 40. - 10 years agoHelpfull: Yes(0) No(0)
- let no. of boys be = b
and no of girls be = g
from the ques. we have,
b=8+g=5(b-g)
solving the above equation we get, no of boys = b =40 - 10 years agoHelpfull: Yes(0) No(0)
- x be the number of girls. boys y=x+8
Given Boys=5 times(y-x)
y=5(x+8-x)=40. - 10 years agoHelpfull: Yes(0) No(0)
- GIVEN THAT
B=G+8
B=5*(B-G)
FROM ABOVE
G+8=5*B-5*G
6*G+8=5*G+40
G=32
THEN B=40 - 10 years agoHelpfull: Yes(0) No(0)
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