Q. Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.

Option
A. 12 sec
B. 24 sec
C. 48 sec
D. 60 sec

• 
  Relative speed = = (45 + 30) km/hr
  = 75 x 5 m/sec
  18
  = 125 m/sec.
  6
  We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
  
  So, distance covered = Length of the slower train.
  
  Therefore, Distance covered = 500 m.
  
  Required time = 500 x 6 = 24 sec.
  125
  
• 12 years agoHelpfull: Yes(5) No(3)
• Relative speed =(45*5/18)+(30*5/18)=125/6,
  Relative distanse both train:500/2=250,
  Now speed=distance/time
  put the value of relative speed and relative distance in above formula
  125/6=250/Time
  by solving
  TIME=12 second
• 6 years agoHelpfull: Yes(1) No(0)
• Option C 48 sec
  Relative speed=45+30=75 Kmph=75*5/18=125/8
  Distance to be covered =500+500=1000
  Time=1000*6/125=48 sec
• 12 years agoHelpfull: Yes(0) No(7)
• Time=Total Distance/Total speed
  Time=1000/(75*5/18)
  Time=12sec
• 10 years agoHelpfull: Yes(0) No(1)
• 
  Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
  A. 12 sec
  B. 24 sec
  C. 48 sec
  D. 60 sec
  Answer: Option B
  
  Explanation:
  
  Relative speed = = (45 + 30) km/hr
  = ( 75 x 5 ( m/sec
  18
  = ( 125 ( m/sec.
  6
  We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
  
  So, distance covered = Length of the slower train.
  
  Therefore, Distance covered = 500 m.
  
  Therefore Required time = ( 500 x 6 ( = 24 sec.
  125
  
• 8 years agoHelpfull: Yes(0) No(0)
• Relative speed = = (45 + 30) km/hr
  = ( 75 x 5 ( m/sec
  18
  = ( 125 ( m/sec.
  6
  We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
  
  So, distance covered = Length of the slower train.
  
  Therefore, Distance covered = 500 m.
  
  Therefore Required time = ( 500 x 6 ( = 24 sec.
• 7 years agoHelpfull: Yes(0) No(0)