IBM
Company
Numerical Ability
Arithmetic
Three numbers are in A.P., and the product of them is same as product of smallest and largest. What
is the middle number?
a) 1 b) -1 c) 2 d) -2
Read Solution (Total 8)
-
- let 3 A.P terms are a,a+d,a+2d
a is the 1st no.
a+d is the middle one and
a+2d is the last no.
According to question a*(a+d)*(a+2d)=a*(a+2d)
=> a+d=1
Therefore middle no.is 1 - 10 years agoHelpfull: Yes(16) No(0)
- let x,y,z are 3 members in ap
they given product of xyz=product of xz
if we subbstitute y=1 in xyz product then we will get it as xz
so y=1 - 10 years agoHelpfull: Yes(1) No(0)
- ans = a(1)
since;
the A.P is-> -1,1,3 so the prdct of them is -3 and the prdct of -1 & 3 is -3.
so the middle term is 1. - 10 years agoHelpfull: Yes(0) No(1)
- assume a,b,c in a.p then given abc=ac so b=1
- 10 years agoHelpfull: Yes(0) No(0)
- (a-d)*a*(a+d)=(a-d)*(a+d)
0r,a=1 - 10 years agoHelpfull: Yes(0) No(0)
- let us assume three values which are in a.p
x,x+1,x+2
as given in the question product of these three values=product of small and largest
i.e x*x+1*x+2=x*x+2
x(x^2+3x+2)=x(x+2)
x(x+2)=0;
x=-2 or 0
if u consider 0 the middle value is 1
if u consider -2 the middle value is -1 - 10 years agoHelpfull: Yes(0) No(0)
- Middle term is 1
suppose all the 3 terms are a-x, a, a+x
so product of the three = product of smallest and largest
therefore (a-x)*a*(a+x)=(a-x)*(a+x)
therefor a=(a-x)*(a+x)/(a-x)*(a+x) =1
- 10 years agoHelpfull: Yes(0) No(0)
- let the 3 nos in AP be a-d,a,a+d
ATQ
(a-d)(a)(a+d)=(a-d)(a+d)
=> a(a^2-d^2)=a^2-d^2) =>a=1
hence ans is a)1 - 9 years agoHelpfull: Yes(0) No(0)
IBM Other Question
WHAT IS THE SYLLABUS FOR APTITUDE AND ENGLISH IN IBM?
PLZ HELP
1) 1/4, 1/4, 1/2, 3/2, 6, ?
2) 0.8, 1.8, 3.6, 3.6, 4.6, 9.2, 9.2, 10.2, ?
3) 22, 19.5, 21.45, 33, 30.5, 33.55, 44, 41.5, ?
4) 15 3/4, 16, 26, 9 1/5, 9, 19, 64 2/3, 65, 75, 30 3/8, ?
5) 3, 2, 1, 4, 5, 4, 5, 1, 0, 6, 3, ?
6) 3/2, 2 1/4, 9/4, 7/2, 12 1/4, 49/4, 4/3, 1 1/7, 16/9, ?
7) 18, 24, 5, 21, 27, 8, 17, 23, 4, 24, 30, ?
8) 100, 98, 95, 90, 83, ?
9) 1, 3, 3, 2, 8, 10, 3, 4, 12, 4, 8, ?
10) 49, 7, 98, 16, 4, 48, 9, 3, 36, 25, 5, ?
11) 9, 12, 4, 8, 12, 15, 5, 9, 3, 6, 2, 6, 6, 9, ?
12) 5/6, 1/3, 1/2, 1/2, 2/8, 1/4, 5/6, 1/6, 2/3, 1/2, 1/3, ?
13) 33, 8, 41, 21, 67, 72, 47, 119, 124, ?
14) 1/7, 3/4, 4/9, 5/6, 7/11, 7/8, ?
15) 7, 4, 6, 3, 4.5, 1.5, 2.25, -0.75, ?