14. If the 4 numbers are arranged in all possible orders then how many
solutions are possible.

• the answer be 4! = 24 ways
• 10 years agoHelpfull: Yes(25) No(0)
• 4! ways...24 ways we can arrange
• 10 years agoHelpfull: Yes(1) No(0)
• 4!=4*3*2*1=24
• 10 years agoHelpfull: Yes(1) No(0)
• if 4 different numbers
  4!=24 ways
  if repeated
  4^4=256
• 10 years agoHelpfull: Yes(1) No(1)
• 24 factorial
• 10 years agoHelpfull: Yes(0) No(1)
• For arrange 4 numbers in all possible ways we need to calculate 4!=24.
  thats all..
• 10 years agoHelpfull: Yes(0) No(0)
• 4X3X2X1 possible ways that is 24 possible ways
• 10 years agoHelpfull: Yes(0) No(0)
• 4! = 24 ways
  for example 2 digit number 23 number of possible ways 23, 32===2!
  so 3 digit number 123 number of possible ways 123,132,231,213,312,321===3!
  so 4 digit number possible ways are 4!=4*3*2*1=24 ways
• 10 years agoHelpfull: Yes(0) No(0)
• 4p4
  4*3*2*1=24ways
• 9 years agoHelpfull: Yes(0) No(0)
• since its mentioned all posible ways thus repitions are also allowed thus 4*4*4*4=256
  If repitions are not allowed then only 4!
• 9 years agoHelpfull: Yes(0) No(0)
• 4!=1*2*3*4=24
• 9 years agoHelpfull: Yes(0) No(0)
• 24 ways..because 4 numbers can be arranged in 4! ways i.e 24 ways
• 9 years agoHelpfull: Yes(0) No(0)