How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?

A. 5 B. 10
C. 15 D. 20

• last position is fixed for 5.
  so for 1st position = 5 choices
  2nd position= 4 choices.
  hence, 5*4*1=20
• 11 years agoHelpfull: Yes(20) No(3)
• there will be 3 position .the last position will be fixd because 5 is only divided by 0 and 5.so the last position will be fixed for the 5.now for 1st 2 position it will be 5p2=20.
  ans=20
• 9 years agoHelpfull: Yes(7) No(3)
• its 20
  as the no. has to be divisible by 5, the unit digit is 5, now we have 5 no.s which have to be at tensd and hundreds place and 5 numbers can be chosen for 2 places in 5*4 i.e, 20 ways.
• 9 years agoHelpfull: Yes(0) No(1)
• answer is 20
• 6 years agoHelpfull: Yes(0) No(0)