f(x)=1+x+x^2+.....x^6 the remainder when f(x^7) is divided by f(X) is

• this question has a confusion.
  you can substitude x=1 and get answer=0
  but if you substitude x=2 you get remainder=7
  and even fermat little theorem gives answer=7
• 9 years agoHelpfull: Yes(9) No(0)
• f(x^7)/f(x)=(1+x^7+x^14+x^21+x^28+x^35+x^42)/(1+x^2+x^3+x^4+x^5+x^6)
  =[1+x^7(1+x^2+x^3+x^4+x^5+x^6)]/(1+x^2+x^3+x^4+x^5+x^6)
  therefore remainder is 1.
• 9 years agoHelpfull: Yes(7) No(3)
• i checked from open seesame... answer is 7 .
• 9 years agoHelpfull: Yes(3) No(0)
• Answer is 0.... :)
• 9 years agoHelpfull: Yes(2) No(1)
• f(x^7)=x^6+x^7+x^8+x^9+x^10+x^11+x^12
  f(x)=1+x+x^2+.....x^6
  f(x^7)/f(x)=(x^6+x^7+x^8+x^9+x^10+x^11+x^12)/(1+x+x^2+.....x^6)=x^6
  ans--x^6
• 9 years agoHelpfull: Yes(2) No(1)
• answer is 7..put x=2
  f(x)=127
  f(x^7)=1+128+128^2+128^3+128^4+128^5+128^6
  f(x^7)/f(x)=1/127+128/127+128^2/127+128^3/127+128^4/127+128^5/127+128^6/127
  =1+1+1+1+1+1+1=7
  
• 9 years agoHelpfull: Yes(2) No(1)
• what is the correct anser..plz tell me some1??
  
• 9 years agoHelpfull: Yes(1) No(0)
• ans is 0 bcoz if we devide both of them they will be exactly devisable..and remainder will be 0...
  
• 9 years agoHelpfull: Yes(1) No(0)