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f(x)=1+x+x^2+.....x^6 the remainder when f(x^7) is divided by f(X) is
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- this question has a confusion.
you can substitude x=1 and get answer=0
but if you substitude x=2 you get remainder=7
and even fermat little theorem gives answer=7 - 10 years agoHelpfull: Yes(9) No(0)
- f(x^7)/f(x)=(1+x^7+x^14+x^21+x^28+x^35+x^42)/(1+x^2+x^3+x^4+x^5+x^6)
=[1+x^7(1+x^2+x^3+x^4+x^5+x^6)]/(1+x^2+x^3+x^4+x^5+x^6)
therefore remainder is 1. - 10 years agoHelpfull: Yes(7) No(3)
- i checked from open seesame... answer is 7 .
- 10 years agoHelpfull: Yes(3) No(0)
- Answer is 0.... :)
- 10 years agoHelpfull: Yes(2) No(1)
- f(x^7)=x^6+x^7+x^8+x^9+x^10+x^11+x^12
f(x)=1+x+x^2+.....x^6
f(x^7)/f(x)=(x^6+x^7+x^8+x^9+x^10+x^11+x^12)/(1+x+x^2+.....x^6)=x^6
ans--x^6 - 10 years agoHelpfull: Yes(2) No(1)
- answer is 7..put x=2
f(x)=127
f(x^7)=1+128+128^2+128^3+128^4+128^5+128^6
f(x^7)/f(x)=1/127+128/127+128^2/127+128^3/127+128^4/127+128^5/127+128^6/127
=1+1+1+1+1+1+1=7
- 10 years agoHelpfull: Yes(2) No(1)
- what is the correct anser..plz tell me some1??
- 10 years agoHelpfull: Yes(1) No(0)
- ans is 0 bcoz if we devide both of them they will be exactly devisable..and remainder will be 0...
- 10 years agoHelpfull: Yes(1) No(0)
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