Taps A, B and C are connected to a water tank and the rate of flow of water is 42 litre/h, 56 lit/h and 48 lit/h respectively. Taps A and B fills the tank while tap c empties the tank. If all the three taps are opened simultaneously, the tank gets completely filled up in 16 hours. What is the capacity of the tank? 1) 960 lit 2) 800 lit 3) 2324 lit 4) 1600 lit

• volume rate * time = volume
  here A,B are doing the positive work, i.e filling the tank
  and C is doing the negative work
  rate of, A -> 42
  B -> 56
  C -> -48
  So, (A+B-C)*time = volume
  volume = (42+56-48)*16 = 50*16=800 litres
  
  so the answer is 2)800 lit
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• there is a little mistake in the previous answer.
  The formula is ( A+B+C), where C is negative.
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• ((A+B)-C)*16=Capacity of the tank,
  so,
  ((42+56)-48)*16
  50*16
  800 liters
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• (42+56-48)*16=800
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• (A+B-C)*time = volume
  volume = (42+56-48)*16 = 50*16=800 litres
  
• 10 years agoHelpfull: Yes(0) No(0)