If a certain number when divided by the numbers 5,3,2 one after other successively, leaves a remainder 0,2,1 Then what will be the remainders if it is divided by the numbers 2,3,5

• Let whatever be the number, it can be formulated as:
  suppose X is the Quotient after having divided the number by 2 then
  the original number = 5(3(2X+1)+2)) //this is formulated using remainder theorem.
  
  Hence original number = 30X+25
  this when divided by 2 will leave 1 as remainder, because 30X is divisible by 2 but 25 fill leave remainder 1.
  After being divided by 2 the number gets modified as 15X+12
  Now, similarly divide this by 3, remainder will be 0 as both 15X and 12 are divisible by 3. then the number is modified as: 5X+4, which on dividing with 5 remains 4.
  therefore, 1,0,4 is the answer!
• 10 years agoHelpfull: Yes(49) No(2)
• The Number is 35 ,When divided by 5,3,2 leaves remainder 0,2,1 respectively.
  
  So if 35 is divided by 2,3,5 leaves remainder 1,2,0 respectively.
• 10 years agoHelpfull: Yes(18) No(9)
• in this can 5 can be taken?and when 5 divided by 2,3,5 remainder will be1,2,0.
  
• 10 years agoHelpfull: Yes(10) No(4)
• z=2+1=3,y=3z+2=11,x=5y+0=55
  55divided by 5,3,2 successively it will give 1,0,4
  
• 10 years agoHelpfull: Yes(9) No(1)
• the no is 25 which gives remainder 0,2,1 when diving by 5,3,2 successively
  
  if 25 is divided by 2,3,5 successively it will give 1,0,4
• 10 years agoHelpfull: Yes(5) No(6)
• yar tmlog division bhul gye kya kha pr 55%2=4 hota h vai kaun se school me pdhe ho
• 10 years agoHelpfull: Yes(2) No(1)
• that will be 5[3{2*X+1}+2],, if we consider x=2.. the no will be 85..then the ans is 1, 0, 4
  
• 10 years agoHelpfull: Yes(1) No(1)
• ANS 1,0,4,
  let x be the given nom.
  first it divide by 5 suppose a be the quotient and reminder is given 0
  so X=5a+0(reminder)
  next time by successively divided a by 3 let b be quotient and reminder is given 2
  so a=3b+2(reminder)
  and so on b=2*1+1=3
  as b=3 so a=11 and X=55 on successively divided X by 2,3,5 the reminder will be 1,0,4
  
• 9 years agoHelpfull: Yes(1) No(1)
• 5 remainder 0
  3 remainder 2
  2 remainder 1
  Now add 2 and 1,it gives 3
  Multiply 3 with the upper value it gives 9 and add with 2
  now multiply 11 with 5 and add with 0
  the no is 55
  when 55 divided by 2,3,5 gives 1,1,0
• 5 years agoHelpfull: Yes(0) No(0)